BE.180:SecondOrderBinding: Difference between revisions

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<center><math>0=-k_{on}*[A]*[B]-k_{off}*[A:B]</math></center>
<center><math>0=-k_{on}*[A]*[B]-k_{off}*[A:B]</math></center>
*Solve for <math>K_D</math>, the dissociation constant.
*Solve for <math>K_D</math>, the dissociation constant.
<center><math>K_D = k_{off}/k_{on} = [A][B]/[A:B]</math></center>
<center><math>K_D = k_{off}/k_{on} = /frac{[A][B]}{[A:B]}</math></center>

Revision as of 17:48, 20 March 2006

Second Order Binding (of two things)

Givens:

  • A physical interaction between molecules A and B.
  • A system that contains some concentration of molecules A and B.

Tasks:

  • Compute the steady state concentrations of free A, free B, and the A:B complex.

Approach:

  • Write differential equation for change in A:B over time.
[math]\displaystyle{ \frac{d[A:B]}{dt}=-k_{on}*[A]*[B]-k_{off}*[A:B] }[/math]
  • Solve equation at steady state (that is, no change in concentration of the A:B complex.
[math]\displaystyle{ 0=-k_{on}*[A]*[B]-k_{off}*[A:B] }[/math]
  • Solve for [math]\displaystyle{ K_D }[/math], the dissociation constant.
[math]\displaystyle{ K_D = k_{off}/k_{on} = /frac{[A][B]}{[A:B]} }[/math]