BISC 219/2009: Mod 1 Lab 3: Difference between revisions

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== Lab 3: Linkage Testing, Backcrossing and Mapping==
== Lab 3: Linkage Testing and Mapping==
 
'''Backcrossing'''<br>
Confirm phenotype of the backcrossed strain; specifically, your backcrossed mutant should breed true meaning that it should produce again a homozygote for the mutation: Genotype d/d;  phenotype mutant; the crosses are the following (P: d/d x +/+, F1: d/+ self fertilizes to produce F2: +/+, d/+ and d/d). Confirm that you get the expected proportion of homozygote recessive mutants<br>
<br>
'''Linkage Testing'''<br>
'''Linkage Testing'''<br>
To determine in what chromosome or linkage group your dpy mutation is located record the number of dpy, unc and dpy unc mutants by examining, scoring the phenotype and removing that animal from the plate for each of your five crosses with reference unc mutations. If you see no double mutants (d u/d u), it could be taken as an indication that your dpy mutation is on the same chromosome or linkage group as that unc mutation.  Remember that your mutation will only reside on a single chromosome; therefore, the ideal result is that your mutation segregates independently with respect to 4 of the 5 reference mutations. In which linkage group is your dpy mutation located?<br>
To determine in what chromosome or linkage group your dpy mutation is located record the number of dpy, unc and dpy unc mutants by examining, scoring the phenotype and removing that animal from the plate for each of your four crosses with reference unc mutations. If you see no double mutants (d u/d u), it could be taken as an indication that your dpy mutation is on the same chromosome or linkage group as that unc mutation.  Remember that your mutation will only reside on a single chromosome; therefore, the ideal result is that your mutation segregates independently with respect to 3 of the 4 reference mutations. If you didn't get 4 successful reference crosses, score those you have and see your instructor for help. Can you determine the linkage group of your dpy mutation?<br>
<br>
<br>
'''Mapping'''<br>
'''Mapping'''<br>
Assuming that you have determined the linkage group on which your mutation resides, you will continue working with that strain only where you suspect that the two mutations are one the same chromosome. To calculate distance between the two markers separate 5 unc mutants to  5 individual plates.  As described above, most of these are wild type for the Dpy mutation (+ u/+ u), but hopefully some are heterozygous for the Dpy mutation (d u/+ u). <br><br>
Assuming that you have determined the linkage group on which your mutation resides, you will continue working with that strain only. You now suspect that the two mutations are on the same chromosome. To begin to calculate distance between the two markers separate 5 dpy mutants to  5 individual plates.  As described above, most of these individuals are wild type for the Unc mutation (+ d/+ d), but hopefully some are heterozygous for the Unc mutation (u d/+ d). How does this happen? <br>
<br>
#Separate 5 dpy mutants to  5 individual plates
#Label each of these plates with "Mapping 1" and your initials and the date with your <font color= purple> '''PURPLE''' </font color= purple> Sharpie.<br>
#Incubate the plates at 23°C for 3 days<br>
<br>
<br>
'''3-4 days later'''<br>
'''3 days later'''<br>  
'''Mapping:''' screen your 5 plates for double mutants. Pick 3 such putative double mutants to separate plates.<br>
#'Screen your 5 plates for double mutants.  
#Pick 3 such putative double mutants to separate plates to allow them to self fertilize.  If they are truly double mutants then all of their progeny should be double mutant as well and the progeny will be used for the next cross.<br>
#Label each of these plates with "Mapping 2", the genotype d u/d u and your initials and the date with your <font color= purple> '''PURPLE''' </font color= purple> Sharpie.<br>
#Incubate the plates at 23°C until next lab period.<br>
<br>
<br>


== Complementation ==
== Complementation ==
It is not unusual to have series of mutations that confer similar phenotypes and also map to a identical or similar location on a chromosome.  In such cases, the practicing geneticist performs a complementation test to determine if the mutations are allelic (that is, in the same gene) or non-allelic. If the mutations are allelic there should be no complementation whereas you could recover the wild type phenotype (though complementation) if the two mutations are on different genes. The specifics of strain construction vary depending on the experimental organism.  However, the basic strategy in all cases is to construct a double heterozygote and then examine the phenotype of this organism.  As mentioned above, a wild-type phenotype indicates that the two mutations complement one another and are therefore in different genes.  Conversely, a mutant phenotype suggests the mutations are allelic to one another (that is, they fail to complement).  Over the next two weeks we will construct five different double hets containing the dumpy mutation of unknown location (dpy-u) and five different dumpy mutations of known location (dpy-k) as follows:<br>
It is not unusual to have series of mutations that confer similar phenotypes and also map to a identical or similar location on a chromosome.  In such cases, the practicing geneticist performs a complementation test to determine if the mutations are allelic (that is, in the same gene) or non-allelic (different genes with the same phenotype). If the mutations are allelic there should be no complementation, whereas you could recover the wild type phenotype (though complementation) if the two mutations are in different genes. The specifics of strain construction vary depending on the experimental organism; however, the basic strategy in all cases is to construct a double heterozygote and then to examine the phenotype of this organism.  Remember that a wild-type phenotype indicates that the two mutations complement one another (cancel each other out) and are therefore in different genes.  Conversely, a mutant phenotype suggests the mutations are allelic to one another (that is, they fail to complement).<br><br>  
 
Over the next two weeks we will construct four different double heterozygotes containing your dumpy mutation of unknown location (dpy-u) and four different dumpy mutations of known location (dpy-k) as follows:<br>
<br>
<br>
First you obtain heterozygotes for the dpy mutation of unknown location<br>
First obtain heterozygotes for your dpy mutation of unknown location through<br>
Cross #1:  unknown Dpy hermaphodites (dpy-u/dpy-u) x N2 males (+/+) yields dpy-u/+ progeny<br>
'''Cross #1:''' unknown Dpy hermaphodites (dpy-u/dpy-u) x N2 males (+/+) yields dpy-u/+ progeny<br>
<br>
<br>
Then you use those heterozygotes in the next cross<br>
Then use those heterozygous males resulting from Cross #1 in the next cross:<br>
Cross #2:  dpy-u/+ males  x known dpy hermaphrodites (dpy-k/dpy-k)  yields half dpy-u +/+ dpy-k progeny<br>
'''Cross #2:''' dpy-u/+ males  x known dpy hermaphrodites (dpy-k/dpy-k)  yields some dpy-u +/+ dpy-k progeny. [Note: we need to use heterozygote males for our unknown dpy mutation (dpy-u/+) because homozygote dumpy males do not mate properly]<br>
<br>
<br>
The phenotype of the double heterozygote is then scored.<br>
The phenotype of the double heterozygote is then scored.<br>
<br>
<br>
As mentioned above, in this experiment you will determine the allelic counterparts of your “unknown” Dpy mutation by placing it (your unknown mutation) with five mutations in different Dpy genes that have been previously mapped (i.e., known mutations).  We are attempting to determine if, our “unknown” Dpy mutations are allelic to any of the five mutations. <br>  
Keep in mind that, in this experiment, you will determine the allelic counterparts of your “unknown” Dpy mutation by placing it (your unknown mutation) with four mutations in different Dpy genes that have been previously mapped (i.e., known mutations).  Our goal is to determine whether or not our “unknown” Dpy mutations are allelic to any of the four mutations. <br>
<br>
<br>
'''3 days after lab:'''
You will set up Cross #1: Cross your unknown Dpy hermaphrodites with N2 males [(dpy-u/dpy-u) x N2 males (+/+)] by placing three to five L4 Dpy's on a new plate with 3-4 N2 males.  You will be picking your own wild type males from a mixed population of worms so be sure to transfer your males to a transfer plate before adding to the crosses.  It is essential that the '''ONLY''' wild-type animals present on this plate are males.(There should be no wild type hermaphrodites because you desire +/dpy males from this plate for the next cross, and not the +/+ males that would result of wild-type hermaphrodites were included on the plate).  Do this in duplicate.<br>
<br>
<br>
In preparation for next week please make sure you can locate a plate of your dpy-u hermaphrodites and one plate of N2 males<br>  
Label your plates with your initials and the date and the genotype dpy/dpy (H) X +/+ (M) with your <font color= orange> '''ORANGE''' </font color= orange> Sharpie.<br>
<br>
<br>
'''3-4 days before lab:'''
Incubate the worms at 23°C until next lab period.<br>
You will set up Cross #1: Cross your unknown Dpy hermaphrodites with N2 males [(dpy-u/dpy-u) x N2 males (+/+)] by placing three to five L4 Dpy's on a plate in the presence of 5 to 8 N2 males.  It is essential that the only wild-type animals present on this plate are males, no wild type hermaphrodites (because you desire +/dpy males from this plate from the next cross, and not the +/+ males that would result of wild-type hermaphrodites were included on the plate).<br><br>
<br>  
Incubate the worms at 23°C until next lab period.<br><br>  
[[BISC 219/2009: Mod 1 C. elegans General Information| ''C. elegans'' General Information]] <br>
[[BISC 219/2009: Mod 1 C. elegans General Information| ''C. elegans'' General Information]] <br>
[[BISC 219/2009: Mod 1 Media and Tools | Tools and Techniques]]<br>
[[BISC 219/2009: Mod 1 Media and Tools | Tools and Techniques]]<br>

Latest revision as of 11:52, 14 October 2009

Wellesley College BISC 219 Genetics

Lab 3: Linkage Testing and Mapping

Linkage Testing
To determine in what chromosome or linkage group your dpy mutation is located record the number of dpy, unc and dpy unc mutants by examining, scoring the phenotype and removing that animal from the plate for each of your four crosses with reference unc mutations. If you see no double mutants (d u/d u), it could be taken as an indication that your dpy mutation is on the same chromosome or linkage group as that unc mutation. Remember that your mutation will only reside on a single chromosome; therefore, the ideal result is that your mutation segregates independently with respect to 3 of the 4 reference mutations. If you didn't get 4 successful reference crosses, score those you have and see your instructor for help. Can you determine the linkage group of your dpy mutation?

Mapping
Assuming that you have determined the linkage group on which your mutation resides, you will continue working with that strain only. You now suspect that the two mutations are on the same chromosome. To begin to calculate distance between the two markers separate 5 dpy mutants to 5 individual plates. As described above, most of these individuals are wild type for the Unc mutation (+ d/+ d), but hopefully some are heterozygous for the Unc mutation (u d/+ d). How does this happen?

  1. Separate 5 dpy mutants to 5 individual plates
  2. Label each of these plates with "Mapping 1" and your initials and the date with your PURPLE Sharpie.
  3. Incubate the plates at 23°C for 3 days


3 days later

  1. 'Screen your 5 plates for double mutants.
  2. Pick 3 such putative double mutants to separate plates to allow them to self fertilize. If they are truly double mutants then all of their progeny should be double mutant as well and the progeny will be used for the next cross.
  3. Label each of these plates with "Mapping 2", the genotype d u/d u and your initials and the date with your PURPLE Sharpie.
  4. Incubate the plates at 23°C until next lab period.


Complementation

It is not unusual to have series of mutations that confer similar phenotypes and also map to a identical or similar location on a chromosome. In such cases, the practicing geneticist performs a complementation test to determine if the mutations are allelic (that is, in the same gene) or non-allelic (different genes with the same phenotype). If the mutations are allelic there should be no complementation, whereas you could recover the wild type phenotype (though complementation) if the two mutations are in different genes. The specifics of strain construction vary depending on the experimental organism; however, the basic strategy in all cases is to construct a double heterozygote and then to examine the phenotype of this organism. Remember that a wild-type phenotype indicates that the two mutations complement one another (cancel each other out) and are therefore in different genes. Conversely, a mutant phenotype suggests the mutations are allelic to one another (that is, they fail to complement).

Over the next two weeks we will construct four different double heterozygotes containing your dumpy mutation of unknown location (dpy-u) and four different dumpy mutations of known location (dpy-k) as follows:

First obtain heterozygotes for your dpy mutation of unknown location through
Cross #1: unknown Dpy hermaphodites (dpy-u/dpy-u) x N2 males (+/+) yields dpy-u/+ progeny

Then use those heterozygous males resulting from Cross #1 in the next cross:
Cross #2: dpy-u/+ males x known dpy hermaphrodites (dpy-k/dpy-k) yields some dpy-u +/+ dpy-k progeny. [Note: we need to use heterozygote males for our unknown dpy mutation (dpy-u/+) because homozygote dumpy males do not mate properly]

The phenotype of the double heterozygote is then scored.

Keep in mind that, in this experiment, you will determine the allelic counterparts of your “unknown” Dpy mutation by placing it (your unknown mutation) with four mutations in different Dpy genes that have been previously mapped (i.e., known mutations). Our goal is to determine whether or not our “unknown” Dpy mutations are allelic to any of the four mutations.


3 days after lab: You will set up Cross #1: Cross your unknown Dpy hermaphrodites with N2 males [(dpy-u/dpy-u) x N2 males (+/+)] by placing three to five L4 Dpy's on a new plate with 3-4 N2 males. You will be picking your own wild type males from a mixed population of worms so be sure to transfer your males to a transfer plate before adding to the crosses. It is essential that the ONLY wild-type animals present on this plate are males.(There should be no wild type hermaphrodites because you desire +/dpy males from this plate for the next cross, and not the +/+ males that would result of wild-type hermaphrodites were included on the plate). Do this in duplicate.

Label your plates with your initials and the date and the genotype dpy/dpy (H) X +/+ (M) with your ORANGE Sharpie.

Incubate the worms at 23°C until next lab period.

C. elegans General Information
Tools and Techniques
Lab 1: Welcome to C. elegans and Mutant Hunt
Lab 2: Linkage Test and Backcross
Lab 4: Mapping Part 2
Lab 5: Score!