BME100 f2013:W900 Group10 L2: Difference between revisions

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'''Experiment 1'''
'''Experiment 1'''
[[Image:Humans2.jpg‎|200px|The data on this graph shows the dosage of LPS given to Humans 60years old and older and the effect it has on their inflammation]]
[[Image:Humans2.jpg‎|800px|The data on this graph shows the dosage of LPS given to Humans 60years old and older and the effect it has on their inflammation]]


'''Experiment 2'''
'''Experiment 2'''

Revision as of 01:16, 18 September 2013

BME 100 Fall 2013 Home
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Lab Write-Up 1 | Lab Write-Up 2 | Lab Write-Up 3
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OUR TEAM

Name: Barrett Anderies
Role(s): Summary/Discussion
Name: Joslin Jose
Role(s): Analysis
Name: Takerra Waters
Role(s): Results
Name: Duran Charles
Role(s)Discriptive Statistic
Name: Liam Williams
Role(s)
Name: student
Role(s)

LAB 2 WRITE-UP

Descriptive Statistics

Experiment 1

TABLE 1: Results of data taken from human subjects representing the different inflammontin protein levels at four different dosage of lipopolysaccharide (LPS).

TABLE 2: The mean and standard deviation of the inflammontin protein levels at dosage levels (0mg, 5mg, 10mg, and 15mg) of LPS. Column graph of the data is plotted below in Results.



Experiment 2

TABLE 1: Results of data taken from rat study representing inflammontin protein levels the dosage of 0mg and 10mg of lipopolysaccharide

TABLE 2: The mean and standard deviation of the inflammontin protein level from dosage levels of 0mg and 10mg of lipopolysaccharide. Column graph of data is plotted below in Results.



(Please report descriptive statistics for both experiments. Please calculate descriptive statistics in Excel.)




Results

Experiment 1 The data on this graph shows the dosage of LPS given to Humans 60years old and older and the effect it has on their inflammation

Experiment 2

The data on this graph shows the dosage of LPS given to Rats and the effect it has on their inflammation (Please include well-labeled graphs of the results.)




Analysis

Experiment 1

According to the one-way ANOVA test, the P-value is 0.49. The p-value in this case is much greater than p-value (0.05) to show significant testing results. Which allows the conclusion that there is no statistical difference between the groups. However, a post-hoc test is performed to further verify the tested data.


Post-Hoc test


(0mg vs. 5mg):0.0000008:0.0167:yes,

(0mgvs. 10mg):0.0000008:0.0167:yes,

(0mgvs.15mg): 0.00000001:0.0167:yes,

(5mgvs.10mg):0.00003 : 0.0167:yes,

(5mgvs.15mg):0.00000005 :0.0167 :yes,

(10mgvs.15mg):0.00000006:0.0167:yes,


According to the post-hoc test, each t-test value within the comparison of two groups are less than the correlated P-value (0.0167). This concludes that there is significance.


Experiment 2

For the rat study, there are only two groups therefore only a t-test is necessary to determine significance.

T-Test


dose(0mg)vs. dose(10mg):0.867403497:0.05:NO


Since the t-test value is grater than the correlated P-value (0.05) there is no significance.

(Using inferential statistics, please determine statistically significant differences in the data.)





Summary/Discussion

Human Study:

The analysis of the data shows a significant correlation between the dosage of lipopolysaccharide and the Inflammotin levels. The p-value from the ANOVA test shows that the largest variation in the data is well within acceptable limits and the t-test shows a significant variation between all doses. Thus we can conclude that lipopolysaccharide does affect Inflammotin levels at all of the tested doses.

Rat Study:

The analysis of the data shows no correlation between the dosage of lipopolysaccharide and the Inflammotin levels. The t-test shows that there is no significance between the two dose groups. Therefore we have failed to disprove our null hypothesis and can say nothing about the correlation between lipopolysaccharide dose and Inflammotin levels in rats.