Elizabeth Polidan Week4

Elizabeth Polidan

BIOL 398.03 / MATH 388

• Loyola Marymount University

• Los Angeles, CA, USA

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Answers to questions in A second chemostat assignment

Figure 1 Original script t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60

Figure 2 t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 30 r = 1.0 K = 5 V = 0.5 u2 = 60

Figure 3 t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.25 u2 = 60

Figure 4 t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.30 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60

Figure 5 t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.45 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60

Figure 6 t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 30