# Elizabeth Polidan Week4

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 Revision as of 02:43, 8 February 2013 (view source) (Added figures to table)← Previous diff Revision as of 03:59, 8 February 2013 (view source) (Added text and lines to separate the two different parts of homework.)Next diff → (2 intermediate revisions not shown.) Line 1: Line 1: {{Elizabeth_Polidan}} {{Elizabeth_Polidan}} + + ---- + + [[Media:Assignment4.pdf|Answers to questions in A second chemostat assignment]] + + ---- + + Plots from running Matlab {| class="wikitable" border="1" {| class="wikitable" border="1" Line 67: Line 75: u2 = 60 u2 = 60 |- |- - | [[Image:Wk4_Fig5.jpg]] + | [[Image:Week4_Fig5.jpg]] |- |- | '''Figure 5''' | '''Figure 5'''

## Revision as of 03:59, 8 February 2013

Elizabeth Polidan

BIOL 398.03 / MATH 388

• Loyola Marymount University
• Los Angeles, CA, USA

Plots from running Matlab

 Figure 1 ```Original script t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60 ``` Figure 2 ```t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 30 r = 1.0 K = 5 V = 0.5 u2 = 60 ``` Figure 3 ``` t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.25 u2 = 60 ``` Figure 4 ``` t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.30 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60 ``` Figure 5 ``` t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.45 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 60 ``` Figure 6 ``` t0 = 0;  % initial time t1 = 100;  % final time c0 = 0;  % initial nutrient conc N0 = 30; c20 = 0; S0 = [c0;N0;c20]; q = 0.15 u = 120 r = 1.0 K = 5 V = 0.5 u2 = 30 ```