IGEM:American University/2009/Notebook/Advanced Experimental Chemistry: Fun Times in Beeghly/2013/03/08
From OpenWetWare
(→Welcome to Advanced Experimental Chemistry) 
(→Today's Procedure) 

Line 10:  Line 10:  
Same procedure as 2/15: Preparing PVOH and 3Chloro2Hydroxypropyltrimethylammonium chloride reacted crystals.  Same procedure as 2/15: Preparing PVOH and 3Chloro2Hydroxypropyltrimethylammonium chloride reacted crystals.  
+  
+  4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3Chloro2Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes.  
+  
+  0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. Thus to make our  
+  0.01% 3Chloro2Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly...  
+  
+  0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH].  
+  
+  1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH].  
+  
+  To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride.  
+  
+  
Revision as of 13:34, 8 March 2013
iGEM Project name 1  Main project page Previous entry Next entry 
Welcome to Advanced Experimental ChemistryToday's ProcedureSame procedure as 2/15: Preparing PVOH and 3Chloro2Hydroxypropyltrimethylammonium chloride reacted crystals. 4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3Chloro2Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes. 0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. Thus to make our 0.01% 3Chloro2Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly... 0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH]. 1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH]. To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride.
