IGEM:American University/2009/Notebook/Advanced Experimental Chemistry: Fun Times in Beeghly/2013/03/08
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Current revision (15:27, 8 March 2013) (view source) (→Today's Procedure) 

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To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride.  To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride.  
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+  Once dissolved, acetone was added to the solutions until, with shaking the vials, they filled with white precipitate. The vials were then left to continue precipitating in the hood until next lab.  
Current revision
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Welcome to Advanced Experimental ChemistryToday's ProcedureSame procedure as 2/15: Preparing PVOH and 3Chloro2Hydroxypropyltrimethylammonium chloride reacted crystals. 4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3Chloro2Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes. 0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. Thus to make our 0.01% 3Chloro2Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly... 0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH]. 1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH]. To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride. Once dissolved, acetone was added to the solutions until, with shaking the vials, they filled with white precipitate. The vials were then left to continue precipitating in the hood until next lab.
Liz and Klare: They gathered the DSC and FTIR data while I set up the new Quaternary Ammonium Films
