IGEM:American University/2009/Notebook/Advanced Experimental Chemistry: Fun Times in Beeghly/2013/03/08
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Welcome to Advanced Experimental ChemistryToday's ProcedureSame procedure as 2/15: Preparing PVOH and 3Chloro2Hydroxypropyltrimethylammonium chloride reacted crystals. 4 sets of 2g PVOH were left to dissolve (as much as possible on a stir plate) in 5mL 0.2M NaOH for 30 minutes. 0.855g of 3Chloro2Hydroxypropyltrimethylammonium chloride was left to dissolve in 5mL 0.2M NaOH for 30 minutes. 0.01%: x/0.855g=0.01%/10%, x=0.000855g. 0.000855g/0.171(g/mL)= 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. Thus to make our 0.01% 3Chloro2Hydroxypropyltrimethylammonium chloride:PVOH, would require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.005mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.995mL extra NaOH 0.2M]. Similarly... 0.1%: Required the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.05mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.95mL extra NaOH]. 1%: Require the 2gPVOH dissolved in 5mL NaOH 0.2M + 0.5mL of the "stock" 3Chloro2Hydroxypropyltrimethylammonium chloride filled to 10mL NaOH 0.2M [4.5mL extra NaOH]. To make the "10%" solution, we used the 4.445mL left over "10% stock" 3Chloro2Hydroxypropyltrimethylammonium chloride solution. To solve for the actual percentage this makes... (4.445mL)(0.171g/mL 3Chloro2Hydroxypropyltrimethylammonium chloride) = 0.760095g 3Chloro2Hydroxypropyltrimethylammonium chloride (0.760095g)/(0.855g)=x%/10% x=8.89% so, the solution is actually 8.89% of PVOH OH groups reacting w 3Chloro2Hydroxypropyltrimethylammonium chloride.
