IGEM:Cambridge/2008/Notebook/Turing Pattern Formation/2008/08/08
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 Turing Pattern Formation
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Result from the transformationof yesterday
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Result for test of ECE112 transformation
On Cm5 plates, we have some colonies for each strains, on Cm5 + Spc 100 plates, no colonies on each plates. This result seems good, however, we forgot to make a control. Since, we had some colonies on control plates, it is possible that our bacillus are resistant to Cm5, even if they are not transformed. We addded some control colonies.
Control with erythromycin
- Prepare erythromycin, stock 5mg/mL : 0.05g in 10mL of SDW
- Prepare plates : add 20μL of Ery (5mg/mL) into 200mL of agar (final concentration : 0.5μg/mL)
- Do several spots on each plate
| Plate | Colonies added from |
|---|---|
| 1 | ECE166 + 100μL of cells (2 different plates) |
| 2 | ECE153 + 100μL of cells (2 different plates) |
| 3 | ECE166 (from glycerol stock) |
| 4 | Control (from a plate of IA771 without antibiotic) |
| 5 | IA771 + ECE112 (05/08) |
| 6 | IA771 + ECE166 (05/08) |
Amylase production screening
- Prepare agar plate with starch
- Starch : 1g of starch in 10mL of SDW
- Add 2mL of Starch solution into 200mL of agar, mix
-Inoculate on different plates : 1A1 +ECE112 (plate from 05/08), IA751 + ECE112 (plate from 05/08) and IA771 + ECE153
