User:Alexander Cvitan/Notebook/Experimental Biological Chemistry Lab/2013/08/28: Difference between revisions
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Concentration of BSA = 15.6μM <br.> | Concentration of BSA = 15.6μM <br.> | ||
=====Amount of Stock Solution Used===== | =====Amount of Stock Solution Used===== | ||
1ml of gold solution is used to prepare the gold nano particles, thus .00254 milli moles of Gold are present.<br.> | |||
In order to have 90 times less BSA than gold we need 2.82*10^5 milli moles of BSA.<br.> | |||
As a result, 1.809 ml of BSA is needed. | |||
====Citrate-AuNP==== | ====Citrate-AuNP==== | ||
=====Stock Solutions===== | |||
Concentration of Gold Solution (HAuCl<sub>4</sub>*3H<sub>2</sub>O) = .245mM <br.> | |||
Concentration of Sodium Citrate (Na<sub>3</sub>C<sub>6</sub>H<sub>5</sub>O<sub>7</sub>*2H<sub>2</sub>O) = 1.01% | |||
Note, 1.5ml of sodium citrate was used instead of 3ml. | |||
===Data=== | ===Data=== | ||
Revision as of 09:38, 31 August 2013
 Biomaterials Design Lab
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ObjectiveTo prepare gold nanoparticles using two separate methods. Procedure taken from Dr. Matt Hartings, found here. ProcedureBSA-AuNPStock SolutionsConcentration of Gold Solution (HAuCl4*3H2O) = 2.54mM <br.> Concentration of BSA = 15.6μM <br.> Amount of Stock Solution Used1ml of gold solution is used to prepare the gold nano particles, thus .00254 milli moles of Gold are present.<br.> In order to have 90 times less BSA than gold we need 2.82*10^5 milli moles of BSA.<br.> As a result, 1.809 ml of BSA is needed. Citrate-AuNPStock SolutionsConcentration of Gold Solution (HAuCl4*3H2O) = .245mM <br.> Concentration of Sodium Citrate (Na3C6H5O7*2H2O) = 1.01% Note, 1.5ml of sodium citrate was used instead of 3ml. Data |
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