# User:Allison K. Alix/Notebook/CHEM-581/2012/10/24

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Preparation of 50 μM Na2SO4
+ + $\frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g$ + + 0.071035 g Na2SO4 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O. + ---- +
Preparation of 50 μM 72 wt% Fe2(SO4)3
+ + $\frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g$ + + 0.144 g 72 wt% Fe2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O. + ---- +
Preparation of 50 μM Al2(SO4)3
+ + $\frac {656.33 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times 10mL = 0.328g$ + + 0.328 g Al2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O. + ---- + + + + [[Image:GraphPorphyrinSolutions.png]] [[Image:GraphPorphyrinSolutions.png]]

## Current revision

Experimental Chemistry Main project page
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## Objective

• Take UV-Vis of porphyrin solutions
• Re-do crosslinking of porphyrin films
• Prepare sulfate solutions

## Description

1. UV-Vis Spectra of porphyrin solutions with the following concentrations were collected:
1. 25μM
2. 12.5μM
3. 6.75μM
4. 3.375μM
5. 1.6875μM
2. 10 mL 50 μM of the following sulfate solutions were prepared:
1. Na2SO4
2. Fe2(SO4)3
3. Al2(SO4)3

## Data

Preparation of 50 μM Na2SO4

$\frac {142.07 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1 L} {1000mL} \times 10mL = 0.071035 g$

0.071035 g Na2SO4 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.

Preparation of 50 μM 72 wt% Fe2(SO4)3

$\frac {72} {100} \times \frac {399.88 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times \frac 10mL = 0.144g$

0.144 g 72 wt% Fe2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.

Preparation of 50 μM Al2(SO4)3

$\frac {656.33 g} {mol} \times \frac {50mmol} {L} \times \frac {10^-3 mol} {1mmol} \times \frac {1L} {1000mL} \times 10mL = 0.328g$

0.328 g Al2(SO4)3 in 10mL H2O to prepare 50mM. Dilute to 50μM by using 10μL 50mM in 9.99mL H2O.

## Notes

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