# User:Allison K. Alix/Notebook/CHEM-581/2012/10/26

(Difference between revisions)
 Revision as of 14:47, 6 November 2012 (view source) (→Description)← Previous diff Current revision (15:30, 6 November 2012) (view source) (→Data) (6 intermediate revisions not shown.) Line 10: Line 10: ==Objective== ==Objective== + + * Take UV-Vis spectra of mixtures of previously prepared salt solutions and porphyrin solution in 1:1 ratio at the same concentrations (50micM) + + * Take IR spectra of films ==Description== ==Description== + # Finish preparing the following ''sulfate solutions'' + ## 10mL 50 μM H2SO4 + ## 10mL 50 μM Fe2(SO4)3 + # Begin taking IR measurements of ''all'' films synthesized thus far ==Data== ==Data== +
Preparation of 50μM H2SO4
+ + $\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL$ + + 0.0266mL = 26.65μL + ---- +
Preparation of 50μM Fe2(SO4)3
+ + $\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g$ + + 0.138 g Fe2(SO4)3 in 10mL H2O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H2O + ---- [[Image:GraphImage.png‎]] [[Image:GraphImage.png‎]]

## Current revision

Experimental Chemistry Main project page
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## Objective

• Take UV-Vis spectra of mixtures of previously prepared salt solutions and porphyrin solution in 1:1 ratio at the same concentrations (50micM)
• Take IR spectra of films

## Description

1. Finish preparing the following sulfate solutions
1. 10mL 50 μM H2SO4
2. 10mL 50 μM Fe2(SO4)3
2. Begin taking IR measurements of all films synthesized thus far

## Data

Preparation of 50μM H2SO4

$\frac {50 x 10^-3 mol} {L} \times \frac {98.07 g} {mol} \times 10mL \times \frac {1L} {1000 mL} \times \frac {1mL} {1.84 g} = 0.0266mL$

0.0266mL = 26.65μL

Preparation of 50μM Fe2(SO4)3

$\frac {278.01 g} {mol} \times \frac {50 x 10^-3 mol} {L} \times \frac {1 L} {1000 mL} \times 10mL = 0.138 g$

0.138 g Fe2(SO4)3 in 10mL H2O to get 50mM. Dilute to 50μM by using 0.01 mL (10μL) in 9.99mL (9990μL) H2O

## Notes

This area is for any observations or conclusions that you would like to note.

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