User:Allison K. Alix/Notebook/Thesis Research/2013/06/12: Difference between revisions
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==Calculating AuNP concentration in g/L== | ==Calculating AuNP concentration in g/L== | ||
1) Calculate the volume of 1 AuNP | |||
Volume of 1 AuNP = 4/3πr<sup>3</sup>, where r = d/2 = 19.25nm | Volume of 1 AuNP = 4/3πr<sup>3</sup>, where r = d/2 = 19.25nm | ||
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V= 2.988x10<sup>17</sup>cm<sup>3</sup> | V= 2.988x10<sup>17</sup>cm<sup>3</sup> | ||
2) Calculate the mass of 1 AuNP | |||
density of Au = 19.3g/cm<sup>3</sup> | |||
19.3g/cm<sup>3</sup> x 2.988x10<sup>17</sup>cm<sup>3</sup> = 5.7668x10<sup>-16</sup> g | |||
Revision as of 10:55, 12 June 2013
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AuNP synthesis
Note: These AuNPs will be used in the silica coating procedure. See calculations below. Calculating AuNP diameter and concentrationλspr= 527nm d= [ln(λspr-λ0/L1)]/L2 where λ0= 512nm, L1= 6.53, and L2=0.0216 (These are fit parameters from theoretical calculations1) d= [ln(527nm-512nm/6.53)]/0.0216 d= 38.5nm c = A450/ε450 c = 1.89/(4.36x109) c = 0.43nM Calculating AuNP concentration in g/L1) Calculate the volume of 1 AuNP Volume of 1 AuNP = 4/3πr3, where r = d/2 = 19.25nm V= 4/3π(19.25x10-9m)3 V= 2.988x1023m3 V= 2.988x1017cm3 2) Calculate the mass of 1 AuNP density of Au = 19.3g/cm3 19.3g/cm3 x 2.988x1017cm3 = 5.7668x10-16 g
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