User:Allison K. Alix/Notebook/Thesis Research/2013/06/12
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(→Calculating AuNP concentration in g/L) 
(→Calculating AuNP concentration in g/L) 

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==Calculating AuNP concentration in g/L==  ==Calculating AuNP concentration in g/L==  
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+  1) Calculate the volume of 1 AuNP  
Volume of 1 AuNP = 4/3πr<sup>3</sup>, where r = d/2 = 19.25nm  Volume of 1 AuNP = 4/3πr<sup>3</sup>, where r = d/2 = 19.25nm  
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V= 2.988x10<sup>17</sup>cm<sup>3</sup>  V= 2.988x10<sup>17</sup>cm<sup>3</sup>  
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+  2) Calculate the mass of 1 AuNP  
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+  density of Au = 19.3g/cm<sup>3</sup>  
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+  19.3g/cm<sup>3</sup> x 2.988x10<sup>17</sup>cm<sup>3</sup> = 5.7668x10<sup>16</sup> g  
Revision as of 13:55, 12 June 2013
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AuNP synthesis
Note: These AuNPs will be used in the silica coating procedure. See calculations below. Calculating AuNP diameter and concentrationλ_{spr}= 527nm d= [ln(λ_{spr}λ_{0}/L_{1})]/L_{2} where λ_{0}= 512nm, L_{1}= 6.53, and L_{2}=0.0216 (These are fit parameters from theoretical calculations^{1}) d= [ln(527nm512nm/6.53)]/0.0216 d= 38.5nm c = A_{450}/ε_{450} c = 1.89/(4.36x10^{9}) c = 0.43nM Calculating AuNP concentration in g/L1) Calculate the volume of 1 AuNP Volume of 1 AuNP = 4/3πr^{3}, where r = d/2 = 19.25nm V= 4/3π(19.25x10^{9}m)^{3} V= 2.988x10^{23}m^{3} V= 2.988x10^{17}cm^{3} 2) Calculate the mass of 1 AuNP density of Au = 19.3g/cm^{3} 19.3g/cm^{3} x 2.988x10^{17}cm^{3} = 5.7668x10^{16} g
