# User:Allison K. Alix/Notebook/Thesis Research/2013/06/12

(Difference between revisions)
 Revision as of 13:55, 12 June 2013 (view source) (→Calculating AuNP concentration in g/L)← Previous diff Revision as of 13:57, 12 June 2013 (view source) (→Calculating AuNP concentration in g/L)Next diff → Line 33: Line 33: ==Calculating AuNP concentration in g/L== ==Calculating AuNP concentration in g/L== - 1) Calculate the volume of 1 AuNP + ''1) Calculate the volume of 1 AuNP'' Volume of 1 AuNP = 4/3πr3, where r = d/2 = 19.25nm Volume of 1 AuNP = 4/3πr3, where r = d/2 = 19.25nm Line 41: Line 41: V= 2.988x1023m3 V= 2.988x1023m3 - V= 2.988x1017cm3 + '''V= 2.988x1017cm3''' - 2) Calculate the mass of 1 AuNP + ''2) Calculate the mass of 1 AuNP'' density of Au = 19.3g/cm3 density of Au = 19.3g/cm3 - 19.3g/cm3 x 2.988x1017cm3 = 5.7668x10-16 g + 19.3g/cm3 x 2.988x1017cm3 = '''5.7668x10-16 g per 1 AuNP''' + + ''3) Calculate # of AuNP in 20mL solution'' + + 0.43x10-9mol/L x 20mL x 1L/1000mL x 6.02x1023AuNP/1 mol = '''5.219x1012 AuNP'''

## Revision as of 13:57, 12 June 2013

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## AuNP synthesis

Note: These AuNPs will be used in the silica coating procedure. See calculations below.

## Calculating AuNP diameter and concentration

λspr= 527nm

d= [ln(λspr0/L1)]/L2

where λ0= 512nm, L1= 6.53, and L2=0.0216 (These are fit parameters from theoretical calculations1)

d= [ln(527nm-512nm/6.53)]/0.0216

d= 38.5nm

c = A450450

c = 1.89/(4.36x109)

c = 0.43nM

## Calculating AuNP concentration in g/L

1) Calculate the volume of 1 AuNP

Volume of 1 AuNP = 4/3πr3, where r = d/2 = 19.25nm

V= 4/3π(19.25x10-9m)3

V= 2.988x1023m3

V= 2.988x1017cm3

2) Calculate the mass of 1 AuNP

density of Au = 19.3g/cm3

19.3g/cm3 x 2.988x1017cm3 = 5.7668x10-16 g per 1 AuNP

3) Calculate # of AuNP in 20mL solution

0.43x10-9mol/L x 20mL x 1L/1000mL x 6.02x1023AuNP/1 mol = 5.219x1012 AuNP