User:Allison K. Alix/Notebook/Thesis Research/2013/07/16
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(→DNA/AuNP Data Analysis) 
(→DNA/AuNP Data Analysis) 

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4πr<sup>2</sup> x c<sub>n</sub> x D x V  4πr<sup>2</sup> x c<sub>n</sub> x D x V  
  4π(5x10<sup>9</sup>m)<sup>2</sup> x 29.67x10<sup>9</sup>mol/L x 3.967x10<sup>7</sup> moles/m<sup>2</sup> x 240.7x10<sup>6</sup>L  +  4π(5x10<sup>9</sup>m)<sup>2</sup> x 29.67x10<sup>9</sup>mol/L x 3.967x10<sup>7</sup> moles/m<sup>2</sup> x 240.7x10<sup>6</sup>L = '''5.358x10<sup>10</sup>moles''' = 0.53nmoles 
Revision as of 14:27, 16 July 2013
UVVis Analysis/Silica Coating Pt. 2  Main project page Previous entry Next entry 
To Do
Silica Coating Procedure1) Prepare the following solutions:
3) Centrifuge solutions at 4000 rpm for one hour 4) Resuspend particles in PBS to a final concentration of 5nM? DNA/AuNP Data AnalysisSee Image:2013 0715 AuNPDNA.xlsx for AuNP/DNA spectra as well as absorbance values and molar extinction coefficients used to calculate concentrations of each in final solutions. Calculating the surface area of 1 AuNP Surface Area of a sphere = 4πr^{2}, r = 5nm 4π(5x10^{9}m)^{2} = 3.14 x 10^{16}m^{2} = 314nm^{2} Calculating the # of AuNP in 240.7μL 29.67nM solution 29.67 x 10^{9}mol/L x 240 x 10^{6}L x 6.02x10^{23} AuNP/mol = 4.299 x 10^{12} AuNP Calculating the Total Surface Area Available for DNA Attachment 4.299 x 10^{12} AuNP x 3.14x10^{16}m^{2}/1 AuNP = 0.001349886 m^{2} Calculating the Number of Moles of DNA Available to Attach 2.225x10^{6}moles/L x 240.7x10^{6}L = 5.3555575 x 10^{10} moles DNA Calculating oligonucleotide density on each particle 5.3555575x10^{10}moles DNA/0.001349886m^{2} AuNP = 3.967x10^{7} moles DNA/m^{2} AuNP (OR 39.67pmol DNA/cm^{2} AuNP) Calculating the amount of oligonucleotide to attach (theoretical) 4πr^{2} x c_{n} x D x V 4π(5x10^{9}m)^{2} x 29.67x10^{9}mol/L x 3.967x10^{7} moles/m^{2} x 240.7x10^{6}L = 5.358x10^{10}moles = 0.53nmoles
