User:Elizabeth Ghias/Notebook/Experimental Biological Chemistry/2012/01/31: Difference between revisions

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==Description==
==Description==
 
# Make 40 mL of a 17.7 uM stock solution of BSA by mixing 0.0468 g BSA with 40 mL water.
# Make 20 mL of a 2.9 mM stock solution of HAuCl<sub>4</sub> by mixing 0.0197 g HAuCl<sub>4</sub> with 20 mL water. 
# Selected a dye from Marker Gene Technologies Inc.




==Data==
==Data==
* Add data and results here...
No data was collected today


==Notes==
==Notes==
This area is for any observations or conclusions that you would like to note.
* The dye that will be used must either have a red shift or blue shift from the absorbance wavelength of the gold nanoparticles and must contain a succinimidyl group.
 
* The dye selected is 5(6)-Carboxynapthofluorescein, N-succinimidyl ester (C<sub>33</sub>H<sub>19</sub>NO<sub>9</sub>. This dye is a long wavelength fluorophore that reacts with terminal and internal lysine residues at a pH of 8-9.  Its fluorescence is pH dependent.  It absorbs at 602 and emits at 672 nm.  
 
Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.
 
[[Category:Course]]
[[Category:Miscellaneous]]
 




Revision as of 11:15, 7 February 2012

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Objective

To create stock solutions for the reactants used to produce gold nanoparticles and to decide which dye should be used for nanoparticle functionalization.

Description

  1. Make 40 mL of a 17.7 uM stock solution of BSA by mixing 0.0468 g BSA with 40 mL water.
  2. Make 20 mL of a 2.9 mM stock solution of HAuCl4 by mixing 0.0197 g HAuCl4 with 20 mL water.
  3. Selected a dye from Marker Gene Technologies Inc.


Data

No data was collected today

Notes

  • The dye that will be used must either have a red shift or blue shift from the absorbance wavelength of the gold nanoparticles and must contain a succinimidyl group.
  • The dye selected is 5(6)-Carboxynapthofluorescein, N-succinimidyl ester (C33H19NO9. This dye is a long wavelength fluorophore that reacts with terminal and internal lysine residues at a pH of 8-9. Its fluorescence is pH dependent. It absorbs at 602 and emits at 672 nm.



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