User:Elizabeth Ghias/Notebook/Experimental Chemistry/2012/10/05: Difference between revisions

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20 ppm SO<sub>4</sub><sup>2-</sup> = 20 mg/L SO<sub>4</sub> · 0.5 L = 10 mg SO<sub>4</sub><sup>2-</sup> · .1 g /1000 mg = 0.01 g SO<sub>4</sub><sup>2-</sup>
20 ppm SO<sub>4</sub><sup>2-</sup> = 20 mg/L SO<sub>4</sub> · 0.5 L = 10 mg SO<sub>4</sub><sup>2-</sup> · .1 g /1000 mg = 0.01 g SO<sub>4</sub><sup>2-</sup>


0.01 g SO<sub>4</sub><sup>2-</sup> ÷ 96.06 g/mole = 1.041 × 10<sup>-4</sup> moles SO<sub>4</sub><sup>2-</sup> · 1 mole CuSO<sub>4</sub>·5H<sub>2</sub>O / 1 mole SO<sub>4</sub><sup>2-</sup>
0.01 g SO<sub>4</sub><sup>2-</sup> ÷ 96.06 g/mole = 1.041 × 10<sup>-4</sup> moles SO<sub>4</sub><sup>2-</sup> · 1 mole CuSO<sub>4</sub>·5H<sub>2</sub>O / 1 mole SO<sub>4</sub><sup>2-</sup> = 1.041 × 10<sup>-4</sup> moles CuSO<sub>4</sub>·5H<sub>2</sub>O
 
1.041 × 10<sup>-4</sup> moles CuSO<sub>4</sub>·5H<sub>2</sub>O · 249.68 g/mole CuSO<sub>4</sub>·5H<sub>2</sub>O = 0.0260 g CuSO<sub>4</sub>·5H<sub>2</sub>O
 
1.041 × 10<sup>-4</sup> moles CuSO<sub>4</sub>·5H<sub>2</sub>O · 1 mole Cu<sup>2+</sup> / 1 mole CuSO<sub>4</sub> = 1.041 × 10<sup>-4</sup> moles Cu<sup>2+</sup>
 





Revision as of 10:19, 8 October 2012

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Objective

To remake the CuSO4·5H2O and Ha2SO4 standards

Description

  • See below for calculations


Data

No data was collected today.

Calculations

20 ppm SO42- = 20 mg/L SO4 · 0.5 L = 10 mg SO42- · .1 g /1000 mg = 0.01 g SO42-

0.01 g SO42- ÷ 96.06 g/mole = 1.041 × 10-4 moles SO42- · 1 mole CuSO4·5H2O / 1 mole SO42- = 1.041 × 10-4 moles CuSO4·5H2O

1.041 × 10-4 moles CuSO4·5H2O · 249.68 g/mole CuSO4·5H2O = 0.0260 g CuSO4·5H2O

1.041 × 10-4 moles CuSO4·5H2O · 1 mole Cu2+ / 1 mole CuSO4 = 1.041 × 10-4 moles Cu2+



Notes

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