User:Elizabeth Ghias/Notebook/Experimental Chemistry/2012/10/05

Objective

To remake the CuSO₄·5H₂O and Ha₂SO₄ standards

Description

1. 0.0258 g CuSO₄·5H₂O was dissolved in 0.5 L water in a volumetric flask to create a 13.23 ppm solution of CuSO₄·5H₂O.

• See below for calculations

Data

No data was collected today.

CuSO₄ Calculations

20 ppm SO₄^2- = 20 mg/L SO₄ · 0.5 L = 10 mg SO₄^2- · .1 g / 1000 mg = 0.01 g SO₄^2-

0.01 g SO₄^2- ÷ 96.06 g/mole = 1.041 × 10^-4 moles SO₄^2- · 1 mole CuSO₄·5H₂O / 1 mole SO₄^2- = 1.041 × 10^-4 moles CuSO₄·5H₂O

1.041 × 10^-4 moles CuSO₄·5H₂O · 249.68 g/mole CuSO₄·5H₂O = 0.0260 g CuSO₄·5H₂O

1.041 × 10^-4 moles CuSO₄·5H₂O · 1 mole Cu²⁺ / 1 mole CuSO₄ = 1.041 × 10^-4 moles Cu²⁺

1.041 × 10^-4 moles Cu²⁺ · 63.546 g/mole Cu²⁺ = 0.0066 g Cu²⁺ · 1000 mg / 1 g = 6.615 g Cu²⁺ ÷0.5 L: = 13.23 mg/L = 13.23 ppm Cu²⁺

Notes

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