# User:Elizabeth Ghias/Notebook/Experimental Chemistry/2012/10/05

(Difference between revisions)
 Revision as of 13:27, 8 October 2012 (view source)← Previous diff Revision as of 13:32, 8 October 2012 (view source)Next diff → Line 46: Line 46: 20 ppm SO42- = 20 mg/L SO4 · 0.5 L = 10 mg SO42- · .1 g / 1000 mg = 0.01 g SO42- 20 ppm SO42- = 20 mg/L SO4 · 0.5 L = 10 mg SO42- · .1 g / 1000 mg = 0.01 g SO42- - 0.01 g SO42- ÷ 96.06 g/mole = 1.041 × 10-4 moles SO42- · 1 mole Na2SO4·5H2O / 1 mole SO42- = 1.041 × 10-4 moles Na2SO4·5H2O + 0.01 g SO42- ÷ 96.06 g/mole = 1.041 × 10-4 moles SO42- · 1 mole Na2SO4 / 1 mole SO42- = 1.041 × 10-4 moles Na2SO4 + + 1.041 × 10-4 moles Na2SO4 · 142.04 g/mole Na2SO4 = 0.0148 g Na2SO4 + + 1.041 × 10-4 moles Na2SO4 · 2 moles Na2+ / 1 mole Na2SO4 = 2.082 × 10-4 moles Na+ + + 2.082 × 10-4 moles Na+ · 22.99 g/mole Na+ = 0.00478 g Na+ · 1000 mg / 1 g = 4.786 mg Na+ ÷ 0.5 L = 9.573 mg/L Na+ = 9.573 ppm Na+ + +

## Revision as of 13:32, 8 October 2012

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## Objective

To remake the CuSO4·5H2O and Ha2SO4 standards

## Description

1. 0.0258 g CuSO4·5H2O was dissolved in 0.5 L water in a volumetric flask to create a 13.23 ppm solution of CuSO4·5H2O.

• See below for calculations

## Data

No data was collected today.

CuSO4 Calculations

20 ppm SO42- = 20 mg/L SO4 · 0.5 L = 10 mg SO42- · .1 g / 1000 mg = 0.01 g SO42-

0.01 g SO42- ÷ 96.06 g/mole = 1.041 × 10-4 moles SO42- · 1 mole CuSO4·5H2O / 1 mole SO42- = 1.041 × 10-4 moles CuSO4·5H2O

1.041 × 10-4 moles CuSO4·5H2O · 249.68 g/mole CuSO4·5H2O = 0.0260 g CuSO4·5H2O

1.041 × 10-4 moles CuSO4·5H2O · 1 mole Cu2+ / 1 mole CuSO4 = 1.041 × 10-4 moles Cu2+

1.041 × 10-4 moles Cu2+ · 63.546 g/mole Cu2+ = 0.0066 g Cu2+ · 1000 mg / 1 g = 6.615 g Cu2+ ÷0.5 L: = 13.23 mg/L = 13.23 ppm Cu2+

Na2SO4 Calculations

20 ppm SO42- = 20 mg/L SO4 · 0.5 L = 10 mg SO42- · .1 g / 1000 mg = 0.01 g SO42-

0.01 g SO42- ÷ 96.06 g/mole = 1.041 × 10-4 moles SO42- · 1 mole Na2SO4 / 1 mole SO42- = 1.041 × 10-4 moles Na2SO4

1.041 × 10-4 moles Na2SO4 · 142.04 g/mole Na2SO4 = 0.0148 g Na2SO4

1.041 × 10-4 moles Na2SO4 · 2 moles Na2+ / 1 mole Na2SO4 = 2.082 × 10-4 moles Na+

2.082 × 10-4 moles Na+ · 22.99 g/mole Na+ = 0.00478 g Na+ · 1000 mg / 1 g = 4.786 mg Na+ ÷ 0.5 L = 9.573 mg/L Na+ = 9.573 ppm Na+

## Notes

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