User:Elizabeth Ghias/Notebook/Experimental Chemistry/2012/10/05
From OpenWetWare
(Difference between revisions)
Line 17:  Line 17:  
*See below for calculations  *See below for calculations  
+  #  
Line 26:  Line 27:  
20 ppm SO<sub>4</sub><sup>2</sup> = 20 mg/L SO<sub>4</sub> · 0.5 L = 10 mg SO<sub>4</sub><sup>2</sup> · .1 g /1000 mg = 0.01 g SO<sub>4</sub><sup>2</sup>  20 ppm SO<sub>4</sub><sup>2</sup> = 20 mg/L SO<sub>4</sub> · 0.5 L = 10 mg SO<sub>4</sub><sup>2</sup> · .1 g /1000 mg = 0.01 g SO<sub>4</sub><sup>2</sup>  
+  
+  0.01 g SO<sub>4</sub><sup>2</sup> ÷ 96.06 g/mole = 1.041 × 10<sup>4</sup> moles SO<sub>4</sub><sup>2</sup> · 1 mole CuSO<sub>4</sub>·5H<sub>2</sub>O / 1 mole SO<sub>4</sub><sup>2</sup>  
+  
+  
==Notes==  ==Notes== 
Revision as of 13:15, 8 October 2012
Experimental Chemistry  Main project page Previous entry Next entry 
ObjectiveTo remake the CuSO_{4}·5H_{2}O and Ha_{2}SO_{4} standards Description
DataNo data was collected today. Calculations 20 ppm SO_{4}^{2} = 20 mg/L SO_{4} · 0.5 L = 10 mg SO_{4}^{2} · .1 g /1000 mg = 0.01 g SO_{4}^{2} 0.01 g SO_{4}^{2} ÷ 96.06 g/mole = 1.041 × 10^{4} moles SO_{4}^{2} · 1 mole CuSO_{4}·5H_{2}O / 1 mole SO_{4}^{2}
NotesThis area is for any observations or conclusions that you would like to note.
