User:Elizabeth Ghias/Notebook/Experimental Chemistry/2013/02/08
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< User:Elizabeth Ghias | Notebook | Experimental Chemistry | 2013 | 02(Difference between revisions)
Current revision (18:01, 8 February 2013) (view source) |
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* Need to get first part of calculation from Klare. | * Need to get first part of calculation from Klare. | ||
| + | 10% Film and Stock solution - 0.214 g phenol in 10 mL | ||
| + | 1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water | ||
| + | 0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water | ||
| - | + | 0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water. | |
Current revision
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ObjectiveTo prepare new films containing phenol, to purify the quaternary ammonium salt prepared on Monday, and to take an NMR of the purified salt. DescriptionPhenol Film Calculations
10% Film and Stock solution - 0.214 g phenol in 10 mL 1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water 0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water 0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water.
Quaternary Ammonium Salt Purification
DataNo data was collected today. Notes
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