User:Elizabeth Ghias/Notebook/Experimental Chemistry/2013/02/08: Difference between revisions
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* Need to get first part of calculation from Klare. | * Need to get first part of calculation from Klare. | ||
10% Film and Stock solution - 0.214 g phenol in 10 mL | |||
1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water | |||
0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water | |||
0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water. | |||
Revision as of 15:01, 8 February 2013
Experimental Chemistry | <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page <html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html> </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> |
ObjectiveTo prepare new films containing phenol, to purify the quaternary ammonium salt prepared on Monday, and to take an NMR of the purified salt. DescriptionPhenol Film Calculations
10% Film and Stock solution - 0.214 g phenol in 10 mL 1% Film: M1V1 = M2V2 → (21.4 M)(X) = (2.14)(0.01 L) → X = 0.001 L = 1 mL phenol stock solution in 9 mL water 0.1% Film: (21.4 M)(X) = (0.214 M)(0.01 L) → X = 0.0001 L = 0.1 mL phenol stock solution in 9.9 mL water 0.01% Film: (21.4 M)(X) = (0.0214 M)(0.01 L) → X = 0.00001 L = 0.01 mL phenol stock solution in 9.99 mL water.
Quaternary Ammonium Salt Purification
DataNo data was collected today. Notes
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