User:Floriane Briere/Notebook/CHEM-496/2012/02/15

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Objective

Today's objective is to perform a dialysis using the solution we made yesterday. The reaction has been running for 24hours in the shaker, allowing the dye to tag our BSA peptides by binding unprotonated lysine. The dialysis is going to allow us to remove the excess of dye which hasn't been able to react with our Gold NPs. This step permits us to purify our solution so that we'll then be able to quantify labelled NPs using fluorescence spectroscopy. The first of our experiment is to lower the pH of our solution so that the reaction stops; to do so, we have to neutralize Tris molecules by using HCl (we have to add an amount of HCl which is equal to the amount of Tris we added yesterday).

Protocol

  • Control solution (tube 1)
  1. Add 16.8µL of HCl (0.948M)
  2. Several minutes in the shaker
  3. Check the pH using the pHmeter (SympHony): pH = 3.20
  4. Add 300µL of Tris buffer
  5. Check the pH using the pHmeter (SympHony): pH = 6.49
  • 166 ratio solution (tube 2)
  1. Add 79µL of HCl (0.948M)
  2. Several minutes in the shaker
  3. Check the pH using the pHmeter (SympHony): pH = 2.72
  4. Add 1mL of Tris buffer
  5. Check the pH using the pHmeter (SympHony): pH = 6.5
  • 70 ratio solution (tube 3)
  1. Add 32µL of HCl (0.948M)
  2. Several minutes in the shaker
  3. Check the pH using the pHmeter (SympHony): pH = 2.92
  4. Add 600µL of Tris buffer
  5. Check the pH using the pHmeter (SympHony): pH = 6.09
  • Run the dialysis into water, the water is going to be changed twice the next day (2/16/12) and then once a day until 2/21/12:
  1. 2/16/12 (thursday) at 9:30am and 5:10pm
  2. 2/17/12 (friday) at 2:15pm
  3. 2/18/12 (saturday) at 1pm
  4. 2/19/12 (sunday) at 2:45pm
  5. 2/20/12 (monday) at 1:15pm

Data

Calculations for the volume of HCl needed to neutralize Tris.

Concentration of Tris buffer = 50mM

Concentration of HCl solution = 0.948M

  • Calculations for the control solution (tube 1)

Volume of Tris buffer = 321µL

=> Number of mole of Tris = 321 x 10^-6 x 50 x 10^-3 = 16µM

=> Volume of HCl solution to add = (1.6 x 10^-5)/0.948 = 16.8µL

  • Calculations for the 166 ratio solution (tube 2)

Volume of Tris buffer = 1.5mL

=> Number of mole of Tris = 1.5 x 10^-3 x 50 x 10^-3 = 75µM

=> Volume of HCl solution to add = (7.5 x 10^-5)/0.948 = 79µL

  • Calculations for the 70 ratio solution (tube 3).

Volume of Tris buffer = 600µL

=> Number of mole of Tris = 600 x 10^-6 x 50 x 10^-3 = 32µM

=> Volume of HCl solution to add = (3.2 x 10^-5)/0.948 = 32µL

Notes

  • For the control solution (with HCl instead of HAuCl4; and with the same amounts as in the 166 ratio solution), the solution's color was a light gradient (from blue to purple); when we added the HCl the solution turned light pink.

  • For the 166 ratio solution (initially the fibers' solution), when we removed it from the shaker it was blue with some dark fibers. When we added the HCl, the solution turned partially pink.

  • For the 70 ratio solution (initially the purple solution), when we removed the solution from the shaker the solution's color was a dark gradient (from purple to blue); when we added the HCl the solution became lighter (with light blue and pink).