User:Khyra A. Neal/Notebook/Chem 571/2014/09/30: Difference between revisions

From OpenWetWare
Jump to navigationJump to search
No edit summary
No edit summary
Line 30: Line 30:


* (0.05 M NaCL) x (58.44 g/mol NaCl) x (1 L /1000 mL) x 25 mL = 0.07305 g NaCl in 25 mL HPLC water
* (0.05 M NaCL) x (58.44 g/mol NaCl) x (1 L /1000 mL) x 25 mL = 0.07305 g NaCl in 25 mL HPLC water


4. Prepare 25 mL of each using serial dilutions: 5 mM, 500 μM, 50 μM, and 5 μM NaCl from 50 mM NaCl stock solution
4. Prepare 25 mL of each using serial dilutions: 5 mM, 500 μM, 50 μM, and 5 μM NaCl from 50 mM NaCl stock solution

Revision as of 08:53, 30 September 2014

Project name <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page
<html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html>

Tasklist

1. Prepare 25 mL 50 mM CaCl2 using HPLC water

  • (0.05 M CaCl2) x (111 g/mol CaCl2) x (1 L/ 1000 mL) x 25 mL = 0.13875 g CaCl2 in 25 mL HPLC water

2. Prepare 25 mL of each using serial dilutions: 5 mM, 500 μM, 50 μM, and 5 μM CaCl2 from 50 mM stock CaCl2

  • 5 mM CaCl2
    • (50 mM CaCl2)(V1) = (5 mM CaCl2)(25 mL) = 2.5 mL of 50 mM CaCl2
  • 500 μM CaCl2
    • (5 mM CaCl2)(V1) = (500 μM CaCl2)(25 mL) = 2.5 mL of 5 mM CaCl2
  • 50 μM CaCl2
    • (500 μM CaCl2)(V1) = (50 μM CaCl2)(25 mL) = 2.5 mL of 500 μM CaCl2
  • 5 μM CaCl2
    • (50 μM CaCl2)(V1) = (5 μM CaCl2)(25 mL) = 2.5 mL of 50 μM CaCl2


3 Prepare 25 mL of 50 mM NaCl using HPLC water

  • (0.05 M NaCL) x (58.44 g/mol NaCl) x (1 L /1000 mL) x 25 mL = 0.07305 g NaCl in 25 mL HPLC water


4. Prepare 25 mL of each using serial dilutions: 5 mM, 500 μM, 50 μM, and 5 μM NaCl from 50 mM NaCl stock solution

  • 5 mM NaCl
    • (50 mM NaCl>)(V1) = (5 mM NaCl)(25 mL) = 2.5 mL of 50 mM CaCl2
  • 500 μM NaCl>
    • (5 mM NaCl)(V1) = (500 μM NaCl)(25 mL) = 2.5 mL of 5 mM NaCl
  • 50 μM NaCl
    • (500 μM NaCl)(V1) = (50 μM NaCl)(25 mL) = 2.5 mL of 500 μM NaCl>
  • 5 μM NaCl>
    • (50 μM NaCl)(V1) = (5 μM NaCl)(25 mL) = 2.5 mL of 50 μM NaCl



Retrieved from "https://openwetware.org/mediawiki/index.php?title=User:Khyra_A._Neal/Notebook/Chem_571/2014/09/30&oldid=824802"