User:Klare Lazor/Notebook/Chem-496-001/2012/02/21: Difference between revisions

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==Objective==
==Objective==
*UV vis of bsa plus dye
* remaking of nano particle dye solutions


==Description==
==Description==
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** buffer 0.6276mL  
** buffer 0.6276mL  
** Au/BSA 11.3724 mL
** Au/BSA 11.3724 mL
** Dye 9.236E-5 g
** Dye 9.236E-5 g ......  .00309L......3.09ml
** Total vol 12 mL
** Total vol 12 mL
*** solution was seen to be fluorescing more than last time. the solution was tinted slight orange/purple.
*** solution was seen to be fluorescing more than last time. the solution was tinted slight orange/purple.
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==Data==
==Data==
* Add data and results here...
[[Image:Uv_bsa+dye_feb_21.png]]


==Notes==
==Notes==
This area is for any observations or conclusions that you would like to note.
*spreading for the BSA +DYE was unusual, repeating experiment to make sure this is a repeating patten. In addition, uv of of just plain protein and fluorescence of plain protein will be taken to see if it contributes to this spread.
*In addition, according to UV the concentration of gold present is around 1µM instead of 0.38µM which was calculated




Revision as of 10:10, 11 April 2012

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Objective

  • UV vis of bsa plus dye
  • remaking of nano particle dye solutions

Description

Concentration Curve

  • 1mL of 0.05M phosphate buffer blank, 1µM of dye, 2 µM of dye, 5 µM of dye, 10 µM of dye, and unknown bsa+dye sample (30µL of solution + 1000µL of buffer)

Remake of nano particles + dye calculations

  • note two different solutions of nano particles were used to make this solution
    • 10:1 ratio Buffer: Acid has to be taken into consideration because we do not want the acid to affect the buffer and change the pH and not deprotonate the cysteine
      • y= buffer x= gold/bsa
      • 0.05 m/L Buffer * xL = 10 ( 0.000276 m/L * yL]
      • x+Y = 0.003L
      • y = 0.003L-x
      • 0.05M/L (x) = 10 (0.000276mols/L x (0.003L-x))
        • x= 1.5693 E-4 L, so buffer is 0.1569mL
        • y=0.003L-1.569347E-4L, so 2.8432mL of au/bsa
    • To determine how much dye
      • BSA mols=0.004mM(2.843mL)= 1.137E-8 mols Au moles= 0.276mM (2.8342mL)= 7.8469E-7 moles
      • BSA Mols * 66,000g/mol= 7.505E-4 grams of BSA x 0.06329 mass ratio of cysteins to bsa= 4.75 E-5 grams cysteine
      • 4.75E-5 g of cysteine / 424.06 g/ mole cysteine= 1.12E-8 moles of Cysteine
      • 1.12E-8 moles of cysteine x 4mol dye/1mol of cysteine = 4.4808 E-8 mols of dye (MW of dye) = 2.309E-3 grams of dyes
  • Stock solution of dye
    • 2.309E-3 * 10mL = 0.2309 g/L
    • .2309 g/L * xL = 2.309E-5 g
    • x= 1E-4L = 100µL


What contained in new solution... just multiplied solution by 4 to get larger volume..

  • This time
    • buffer 0.6276mL
    • Au/BSA 11.3724 mL
    • Dye 9.236E-5 g ...... .00309L......3.09ml
    • Total vol 12 mL
      • solution was seen to be fluorescing more than last time. the solution was tinted slight orange/purple.
  • Last time
    • buffer 0.1569mL
    • Au/ Bsa 2.8431 mL
    • Dye 2.309E-5 g
    • Total vol 3 mL

Data

Notes

  • spreading for the BSA +DYE was unusual, repeating experiment to make sure this is a repeating patten. In addition, uv of of just plain protein and fluorescence of plain protein will be taken to see if it contributes to this spread.
  • In addition, according to UV the concentration of gold present is around 1µM instead of 0.38µM which was calculated


Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.


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