User:Mary Mendoza/Notebook/CHEM572 Exp. Biological Chemistry II/2013/01/23: Difference between revisions
From OpenWetWare
Mary Mendoza (talk | contribs) |
Mary Mendoza (talk | contribs) |
||
Line 10: | Line 10: | ||
.030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine | .030 <math>\frac{mol}{L}</math> mol of adenosine × <math>\frac{267.24 g}{1 mol}</math> = <math>\frac{8.0172 g}{L}</math> × .010 L = 0.0802 g of adenosine | ||
[[Image:ADA_kinetics_table.png|px80]] | |||
Revision as of 13:27, 23 January 2013
Project name | <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html> |
Calculation of reagents for ADA kinetic assay
.030 [math]\displaystyle{ \frac{mol}{L} }[/math] mol of adenosine × [math]\displaystyle{ \frac{267.24 g}{1 mol} }[/math] = [math]\displaystyle{ \frac{8.0172 g}{L} }[/math] × .010 L = 0.0802 g of adenosine
|