User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/08/29

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Preparation of Gold and Bovine Serum Albumin Stock Solutions

  • Using a metal spatula, Bovine Serum Albumin (BSA) was prepared by dissolving .0249 g of white crystalline powder of BSA into .025 L of water to obtain 15 μM of BSA.
  • The amount of .0249 g of BSA was acquired from the following calculation:

.025 L of water × (15×10-6 mM of BSA ÷ 1 L of water) = 3.75×10-7 mM of BSA

3.75×10-7 mM of BSA × 66430 g (formula weight of BSA) = .0249 g of BSA

  • Using a metal spatula, Gold (Au) stock solution was made by dissolving .085 g of hydrogen tetrachloroaurate (HAuCl4) in .025 L of water to obtain 10 mM HAuCl4.
  • The amount of .085 g of HAuCl4 was acquired from the following calculation:

.025 L of water × (10×10-3 mM of HAuCl4 ÷ 1L of water)= .00025 mM of HAuCl4

.00025 mM of HAuCl4 × 339. 79 g (formula weight of HAuCl4)= .085 g of HAuCl4

Preparation of different mole ratios of Au/BSA

  • It was decided to prepare solutions of mole ratios; 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. The total volume to be prepared for each mole ratio solution is 6 mL.
  • After allowing some time for the stock solutions of Au and BSA to completely dissolve, calculations were made to verify the volume needed of each constituent, Au, BSA, and water, to obtain the appropriate mole ratio.
  • Using the dilution equation, M1V1 = M2V2, the following calculations were made:

For mole ratio 60

M1 = 15 μM

V1 = Volume needed for BSA to complete ratio

M2 = 1.5 μM (concentration of BSA for mole ratio 60)

V2 = 6 mL (total volume of final solution)



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