User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/02: Difference between revisions
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x<sub>60 mL</sub> = | x<sub>60 mL</sub> = <math>\frac{.060 L of H_2_O * 53. 61 g}{1L}</math> | ||
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Revision as of 19:32, 6 October 2012
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Preparation of the Reactants of HRP Oxidase Assay
0.020 mol of Na2HPO4 × [math]\displaystyle{ \frac{268.07g}{1mol} }[/math] of Na2HPO4 = 53.61 g of Na2HPO4
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