# User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/16

(Difference between revisions)
 Revision as of 01:34, 26 October 2012 (view source) (→PCR mutation)← Previous diff Revision as of 01:39, 26 October 2012 (view source) (→PCR mutation)Next diff → Line 14: Line 14: $\frac{0.46E6 ng}{x \mu L}$ = $\frac{100 ng}{1 \mu L}$ of primer in water = 4600 μL of water $\frac{0.46E6 ng}{x \mu L}$ = $\frac{100 ng}{1 \mu L}$ of primer in water = 4600 μL of water + + * There is limited space in the plastic container (1 mL). Instead of dissolving 0.46E6 ng of the primer in 4600 μL of water, the entire primer was dissolved in 1 mL water. + * Using M1V1 = M2V2, the volume taken from the solution of 0.46E6 ng in 1 mL of water

## Revision as of 01:39, 26 October 2012

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## PCR mutation

• In reference to the PCR Mutation protocol, 100 ng/μL of the primer was needed for the reaction. The weight of the primer in the provided container was 0.46 mg. A ratio of the weight over volume was equated to the required concentration of the primer:

0.46 mg = 0.46E6 ng

$\frac{0.46E6 ng}{x \mu L}$ = $\frac{100 ng}{1 \mu L}$ of primer in water = 4600 μL of water

• There is limited space in the plastic container (1 mL). Instead of dissolving 0.46E6 ng of the primer in 4600 μL of water, the entire primer was dissolved in 1 mL water.
• Using M1V1 = M2V2, the volume taken from the solution of 0.46E6 ng in 1 mL of water