User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/16
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(Difference between revisions)
(→Continuation of Chemiluminescence) 
(→Continuation of Chemiluminescence) 

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<math>\frac{1.91 g}{15 mL}</math> × <math>\frac{1 mol}{105.9784 g}</math> = <math>\frac{0.00120 mol}{mL}</math> × <math>\frac{1 mL}{1E(3) L}</math> = <math>\frac{1.20 mol}{L}</math> = 1.20 M of sodium carbonate  <math>\frac{1.91 g}{15 mL}</math> × <math>\frac{1 mol}{105.9784 g}</math> = <math>\frac{0.00120 mol}{mL}</math> × <math>\frac{1 mL}{1E(3) L}</math> = <math>\frac{1.20 mol}{L}</math> = 1.20 M of sodium carbonate  
+  
+  * The concentration of luminol has been diluted by the addition of 15 mL of water.  
+  
+  Molarity of diluted luminol = <math>\frac{10 mM * 6 mL}{21 mL}</math> = 2.85714 mM of luminol  
Revision as of 02:38, 26 October 2012
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PCR mutation
0.46 mg = 0.46E6 ng
Continuation of Chemiluminescence
× = × = = 1.20 M of sodium carbonate
Molarity of diluted luminol = = 2.85714 mM of luminol
