# User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/16

(Difference between revisions)
 Revision as of 02:35, 26 October 2012 (view source) (→Continuation of Chemiluminescence)← Previous diff Revision as of 02:38, 26 October 2012 (view source) (→Continuation of Chemiluminescence)Next diff → Line 33: Line 33: $\frac{1.91 g}{15 mL}$ × $\frac{1 mol}{105.9784 g}$ = $\frac{0.00120 mol}{mL}$ × $\frac{1 mL}{1E(-3) L}$ = $\frac{1.20 mol}{L}$ = 1.20 M of sodium carbonate $\frac{1.91 g}{15 mL}$ × $\frac{1 mol}{105.9784 g}$ = $\frac{0.00120 mol}{mL}$ × $\frac{1 mL}{1E(-3) L}$ = $\frac{1.20 mol}{L}$ = 1.20 M of sodium carbonate + + * The concentration of luminol has been diluted by the addition of 15 mL of water. + + Molarity of diluted luminol = $\frac{10 mM * 6 mL}{21 mL}$ = 2.85714 mM of luminol

## Revision as of 02:38, 26 October 2012

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## PCR mutation

• In reference to the PCR Mutation protocol, 100 ng/μL of the primer was needed for the reaction. The weight of the primer in the provided container was 0.46 mg. A ratio of the weight over volume was equated to the required concentration of the primer:

0.46 mg = 0.46E6 ng

$\frac{0.46E6 ng}{x \mu L}$ = $\frac{100 ng}{1 \mu L}$ of primer in water = 4600 μL of water

• There is limited space in the plastic container (1 mL). Instead of dissolving 0.46E6 ng of the primer in 4600 μL of water, the entire primer was dissolved in 1 mL water.
• Using M1V1 = M2V2, the volume taken from the solution of 0.46E6 ng in 1 mL of water was calculated to be 217.39 μL. This was transferred to a new tube and filled up with water to a total volume of 1 mL.

V1 = $\frac{100 ng/ \mu L * 1000 \mu L}{0.46E3 ng/ \mu L}$ = 217.39 μL of the dissolved primer in water

• The procedure listed in PCR Mutation protocol was strictly followed. After the addition of all reagents, the sample was placed in the thermocycler.

## Continuation of Chemiluminescence

• The luminol prepared from the previous chemiluminescence laboratory period had a pH of 7 to 8. Reviewing a journal article of Xiaoyu, it was determined that the optimal pH of luminol was 12.5. As a result, it was decided to prepare a new solution of luminol at a pH of 10 to 11.
• A weight of .0112 g of luminol was added to 6 mL of water. The buffer composed of a direct addition of .0737 g of sodium carbonate and .4358 g of sodium bicarbonate.
• Using a pH meter, the electrode detected the pH at 8.73. As suggested by Dr. Hartings, a solution of sodium carbonate was made to increase the pH of the solution.
• Several adjustments were made in increasing the pH. A total weight of 1.91 g of sodium carbonate dissolved in 15 mL of water was added to the 6 mL solution of luminol.
• The molarity of sodium carbonate (MW 105.9784 g/mol) added was calculated:

$\frac{1.91 g}{15 mL}$ × $\frac{1 mol}{105.9784 g}$ = $\frac{0.00120 mol}{mL}$ × $\frac{1 mL}{1E(-3) L}$ = $\frac{1.20 mol}{L}$ = 1.20 M of sodium carbonate

• The concentration of luminol has been diluted by the addition of 15 mL of water.

Molarity of diluted luminol = $\frac{10 mM * 6 mL}{21 mL}$ = 2.85714 mM of luminol