User:Matt Hartings/Notebook/AU Biomaterials Design Lab/2016/08/29: Difference between revisions
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==Description== | ==Description== | ||
# | <u>stock solutions</u> | ||
# 1 L of 0.001 M HCl | |||
## Concentrated HCl should be: 11.65 M | |||
## M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
## (11.65 M)(V<sub>1</sub>) = (0.001M)(1L) | |||
## V<sub>1</sub> = 85.8 μL | |||
# 1 L of 0.001 M HNO<sub>3</sub> | |||
## Concentrated HNO<sub>3</sub> should be: 15.8 M | |||
## M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
## (15.8 M)(V<sub>1</sub>) = (0.001M)(1L) | |||
## V<sub>1</sub> = 63.2 μL | |||
# 1 L of 1 M NaOH | |||
## MW of NaOH = 39.997 g/mol | |||
## M = (m/MW)/V | |||
## 1 M = (m/39.997 g/mol)/1L | |||
## m = 39.997 g | |||
# 1 L of 0.001 M NaOH | |||
## Use 1M stock solution | |||
## M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
## (1 M)(V<sub>1</sub>) = (0.001M)(1L) | |||
## V<sub>1</sub> = 1 mL | |||
# 10 mL of 12.5 mM Fructose | |||
## MW = 180.16 g/mol | |||
## 0.0125 M = (m/180.16 g/mol)/(0.010 L) | |||
## m = 22.5 mg | |||
# 10 mL of 2.5 mM AuCl<sub>3</sub> | |||
## MW = 303.33 g/mol | |||
## 0.0025 M = (m/303.33 g/mol)/(0.010 L) | |||
## m = 7.58 mg | |||
<u> sample solutions </u> | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 4 ([H<sup>+</sup>] = 1x10<sup>-4</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of HCl stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL) | |||
### V<sub>HCl stock</sub> = 0.5 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> | |||
### V<sub>water</sub> = 4 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 5 ([H<sup>+</sup>] = 1x10<sup>-5</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of HCl stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL) | |||
### V<sub>HCl stock</sub> = 0.05 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> | |||
### V<sub>water</sub> = 4.45 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 6 ([H<sup>+</sup>] = 1x10<sup>-6</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of HCl stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL) | |||
### V<sub>HCl stock</sub> = 0.005 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> | |||
### V<sub>water</sub> = 4.495 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 7 ([H<sup>+</sup>] = 1x10<sup>-7</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of HCl stock | |||
### V<sub>HCl stock</sub> = 0 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> | |||
### V<sub>water</sub> = 4.5 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 8 ([H<sup>+</sup>] = 1x10<sup>-8</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of 0.001 M NaOH stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL) | |||
### V<sub>NaOH stock</sub> = 0.005 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> | |||
### V<sub>water</sub> = 4.495 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 9 ([H<sup>+</sup>] = 1x10<sup>-9</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of 0.001 M NaOH stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL) | |||
### V<sub>NaOH stock</sub> = 0.05 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> | |||
### V<sub>water</sub> = 4.45 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 10 ([H<sup>+</sup>] = 1x10<sup>-10</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of 0.001 M NaOH stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL) | |||
### V<sub>NaOH stock</sub> = 0.5 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> | |||
### V<sub>water</sub> = 4 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 11 ([H<sup>+</sup>] = 1x10<sup>-11</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of 1 M NaOH stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1 M)V<sub>1</sub> = (1x10<sup>-3</sup> M)(5 mL) | |||
### V<sub>NaOH stock</sub> = 0.005 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> | |||
### V<sub>water</sub> = 4.495 mL | |||
# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 12 ([H<sup>+</sup>] = 1x10<sup>-12</sup> M), 5 mL total | |||
## Volume of AuCl<sub>3</sub> stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL) | |||
### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL | |||
## Volume of fructose stock | |||
### V<sub>fructose stock</sub> = 0 mL | |||
## Volume of 1 M NaOH stock | |||
### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub> | |||
### (1 M)V<sub>1</sub> = (1x10<sup>-2</sup> M)(5 mL) | |||
### V<sub>NaOH stock</sub> = 0.05 mL | |||
## Volume of water | |||
### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> | |||
### V<sub>water</sub> = 4.45 mL | |||
==Data== | ==Data== |
Revision as of 09:58, 29 August 2016
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ObjectiveCalculations for stock solutions to be made tomorrow. Descriptionstock solutions
sample solutions
Data
NotesThis area is for any observations or conclusions that you would like to note.
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