User:Matt Hartings/Notebook/AU Biomaterials Design Lab/2016/08/29: Difference between revisions

Revision as of 07:16, 30 August 2016

Biomaterials Design Lab

<html><img src="/images/9/94/Report.png" border="0" /></html> Main project page
<html><img src="/images/c/c3/Resultset_previous.png" border="0" /></html>Previous entry<html>      </html>Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html>

Objective

Calculations for stock solutions to be made tomorrow.

Description

stock solutions

1 L of 0.001 M HCl
1. Concentrated HCl should be: 11.65 M
2. M₁V₁ = M₂V₂
3. (11.65 M)(V₁) = (0.001M)(1L)
4. V₁ = 85.8 μL
1 L of 0.001 M HNO₃
1. Concentrated HNO₃ should be: 15.8 M
2. M₁V₁ = M₂V₂
3. (15.8 M)(V₁) = (0.001M)(1L)
4. V₁ = 63.2 μL
1 L of 1 M NaOH
1. MW of NaOH = 39.997 g/mol
2. M = (m/MW)/V
3. 1 M = (m/39.997 g/mol)/1L
4. m = 39.997 g
1 L of 0.001 M NaOH
1. Use 1M stock solution
2. M₁V₁ = M₂V₂
3. (1 M)(V₁) = (0.001M)(1L)
4. V₁ = 1 mL
10 mL of 12.5 mM Fructose
1. MW = 180.16 g/mol
2. 0.0125 M = (m/180.16 g/mol)/(0.010 L)
3. m = 22.5 mg
10 mL of 2.5 mM AuCl₃
1. MW = 303.33 g/mol
2. 0.0025 M = (m/303.33 g/mol)/(0.010 L)
3. m = 7.58 mg
Protein (BSA)
1. MW = 66776 g/mol
2. 30 μM = (m/66776 g/mol)/(0.010 L)
3. m = 20.0 mg

sample solutions

0.25 mM AuCl₃, 0 mM fructose, pH 4 ([H⁺] = 1x10^-4 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{HCl stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.483 mL
0.25 mM AuCl₃, 0 mM fructose, pH 5 ([H⁺] = 1x10^-5 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{HCl stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.933 mL
0.25 mM AuCl₃, 0 mM fructose, pH 6 ([H⁺] = 1x10^-6 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{HCl stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 7 ([H⁺] = 1x10^-7 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. V_{HCl stock} = 0 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.983 mL
0.25 mM AuCl₃, 0 mM fructose, pH 8 ([H⁺] = 1x10^-8 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 9 ([H⁺] = 1x10^-9 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.933 mL
0.25 mM AuCl₃, 0 mM fructose, pH 10 ([H⁺] = 1x10^-10 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{NaOH stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.483 mL
0.25 mM AuCl₃, 0 mM fructose, pH 11 ([H⁺] = 1x10^-11 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-3 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 12 ([H⁺] = 1x10^-12 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-2 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.933 mL

Data

Add data and results here...

Notes

This area is for any observations or conclusions that you would like to note.

Use categories like tags. Change the "Course" category to the one corresponding to your course. The "Miscellaneous" tag can be used for particular experiments, as instructed by your professor. Please be sure to change or delete this tag as required so that the categories remain well organized.

@@ Line 43: / Line 43: @@
 ## 0.0025 M = (m/303.33 g/mol)/(0.010 L)
 ## m = 7.58 mg
+# Protein (BSA)
+## MW = 66776 g/mol
+## 30 μM = (m/66776 g/mol)/(0.010 L)
+## m = 20.0 mg
 <u> sample solutions </u>
@@ Line 56: / Line 60: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL)
 ### V<sub>HCl stock</sub> = 0.5 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4 mL
+### V<sub>water</sub> = 3.483 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 5 ([H<sup>+</sup>] = 1x10<sup>-5</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 70: / Line 78: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL)
 ### V<sub>HCl stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.45 mL
+### V<sub>water</sub> = 3.933 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 6 ([H<sup>+</sup>] = 1x10<sup>-6</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 84: / Line 96: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL)
 ### V<sub>HCl stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.495 mL
+### V<sub>water</sub> = 3.978 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 7 ([H<sup>+</sup>] = 1x10<sup>-7</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 96: / Line 112: @@
 ## Volume of HCl stock
 ### V<sub>HCl stock</sub> = 0 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.5 mL
+### V<sub>water</sub> = 3.983 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 8 ([H<sup>+</sup>] = 1x10<sup>-8</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 110: / Line 130: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL)
 ### V<sub>NaOH stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.495 mL
+### V<sub>water</sub> = 3.978 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 9 ([H<sup>+</sup>] = 1x10<sup>-9</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 124: / Line 148: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL)
 ### V<sub>NaOH stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.45 mL
+### V<sub>water</sub> = 3.933 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 10 ([H<sup>+</sup>] = 1x10<sup>-10</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 138: / Line 166: @@
 ### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL)
 ### V<sub>NaOH stock</sub> = 0.5 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4 mL
+### V<sub>water</sub> = 3.483 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 11 ([H<sup>+</sup>] = 1x10<sup>-11</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 152: / Line 184: @@
 ### (1 M)V<sub>1</sub> = (1x10<sup>-3</sup> M)(5 mL)
 ### V<sub>NaOH stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.495 mL
+### V<sub>water</sub> = 3.978 mL
 # 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 12 ([H<sup>+</sup>] = 1x10<sup>-12</sup> M), 5 mL total
 ## Volume of AuCl<sub>3</sub> stock
@@ Line 166: / Line 202: @@
 ### (1 M)V<sub>1</sub> = (1x10<sup>-2</sup> M)(5 mL)
 ### V<sub>NaOH stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
 ## Volume of water
-### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub>
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
-### V<sub>water</sub> = 4.45 mL
+### V<sub>water</sub> = 3.933 mL
 ==Data==

User:Matt Hartings/Notebook/AU Biomaterials Design Lab/2016/08/29: Difference between revisions

Revision as of 07:16, 30 August 2016

Objective

Description

Data

Notes

Navigation menu

Page actions

Page actions

Personal tools

Navigation

Search

research

Tools