User:Matt Hartings/Notebook/AU Biomaterials Design Lab/2016/08/29: Difference between revisions

Revision as of 07:32, 30 August 2016

Biomaterials Design Lab

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Objective

Calculations for stock solutions to be made tomorrow.

Description

stock solutions

1 L of 0.001 M HCl
1. Concentrated HCl should be: 11.65 M
2. M₁V₁ = M₂V₂
3. (11.65 M)(V₁) = (0.001M)(1L)
4. V₁ = 85.8 μL
1 L of 0.001 M HNO₃
1. Concentrated HNO₃ should be: 15.8 M
2. M₁V₁ = M₂V₂
3. (15.8 M)(V₁) = (0.001M)(1L)
4. V₁ = 63.2 μL
1 L of 1 M NaOH
1. MW of NaOH = 39.997 g/mol
2. M = (m/MW)/V
3. 1 M = (m/39.997 g/mol)/1L
4. m = 39.997 g
1 L of 0.001 M NaOH
1. Use 1M stock solution
2. M₁V₁ = M₂V₂
3. (1 M)(V₁) = (0.001M)(1L)
4. V₁ = 1 mL
10 mL of 12.5 mM Fructose
1. MW = 180.16 g/mol
2. 0.0125 M = (m/180.16 g/mol)/(0.010 L)
3. m = 22.5 mg
10 mL of 2.5 mM AuCl₃
1. MW = 303.33 g/mol
2. 0.0025 M = (m/303.33 g/mol)/(0.010 L)
3. m = 7.58 mg
Protein (BSA)
1. MW = 66776 g/mol
2. 30 μM = (m/66776 g/mol)/(0.010 L)
3. m = 20.0 mg

sample solutions

0.25 mM AuCl₃, 0 mM fructose, pH 4 ([H⁺] = 1x10^-4 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{HCl stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.483 mL
0.25 mM AuCl₃, 0 mM fructose, pH 5 ([H⁺] = 1x10^-5 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{HCl stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.933 mL
0.25 mM AuCl₃, 0 mM fructose, pH 6 ([H⁺] = 1x10^-6 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{HCl stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 7 ([H⁺] = 1x10^-7 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of HCl stock
  1. V_{HCl stock} = 0 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.983 mL
0.25 mM AuCl₃, 0 mM fructose, pH 8 ([H⁺] = 1x10^-8 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 9 ([H⁺] = 1x10^-9 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.933 mL
0.25 mM AuCl₃, 0 mM fructose, pH 10 ([H⁺] = 1x10^-10 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{NaOH stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.483 mL
0.25 mM AuCl₃, 0 mM fructose, pH 11 ([H⁺] = 1x10^-11 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-3 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.978 mL
0.25 mM AuCl₃, 0 mM fructose, pH 12 ([H⁺] = 1x10^-12 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. V_{fructose stock} = 0 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-2 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.933 mL
0.25 mM AuCl₃, 0 mM fructose, pH 4 ([H⁺] = 1x10^-4 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{HCl stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.458 mL
0.25 mM AuCl₃, 0 mM fructose, pH 5 ([H⁺] = 1x10^-5 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{HCl stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.908 mL
0.25 mM AuCl₃, 0 mM fructose, pH 6 ([H⁺] = 1x10^-6 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of HCl stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{HCl stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.953 mL
0.25 mM AuCl₃, 0 mM fructose, pH 7 ([H⁺] = 1x10^-7 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of HCl stock
  1. V_{HCl stock} = 0 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{HCl stock} - V_{Protein Stock}
  2. V_water = 3.958 mL
0.25 mM AuCl₃, 0 mM fructose, pH 8 ([H⁺] = 1x10^-8 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-6 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.953 mL
0.25 mM AuCl₃, 0 mM fructose, pH 9 ([H⁺] = 1x10^-9 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-5 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.908 mL
0.25 mM AuCl₃, 0 mM fructose, pH 10 ([H⁺] = 1x10^-10 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of 0.001 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1x10^-3 M)V₁ = (1x10^-4 M)(5 mL)
  3. V_{NaOH stock} = 0.5 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.458 mL
0.25 mM AuCl₃, 0 mM fructose, pH 11 ([H⁺] = 1x10^-11 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-3 M)(5 mL)
  3. V_{NaOH stock} = 0.005 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.953 mL
0.25 mM AuCl₃, 0 mM fructose, pH 12 ([H⁺] = 1x10^-12 M), 5 mL total
1. Volume of AuCl₃ stock
  1. M₁V₁ = M₂V₂
  2. (0.0025 M)V₁ = (0.00025 M)(5 mL)
  3. V_{AuCl₃ stock} = 0.5 mL
2. Volume of fructose stock
  1. M₁V₁ = M₂V₂
  2. (0.0125 M)V₁ = (0.0000625 M)(5 mL)
  3. V_{fructose stock} = 0.025 mL
3. Volume of 1 M NaOH stock
  1. M₁V₁ = M₂V₂
  2. (1 M)V₁ = (1x10^-2 M)(5 mL)
  3. V_{NaOH stock} = 0.05 mL
4. Volume of Protein stock
  1. M₁V₁ = M₂V₂
  2. (30 μM)V_{Protein Stock} = (3.1 μM))(5 mL)
  3. V_{Protein Stock} = 0.517 mL
5. Volume of water
  1. V_water = 5 mL - V_{AuCl₃ stock} - V_{fructose stock} - V_{NaOH stock} - V_{Protein Stock}
  2. V_water = 3.908 mL

Data

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Notes

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@@ Line 209: / Line 209: @@
 ### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
 ### V<sub>water</sub> = 3.933 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 4 ([H<sup>+</sup>] = 1x10<sup>-4</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of HCl stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL)
+### V<sub>HCl stock</sub> = 0.5 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.458 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 5 ([H<sup>+</sup>] = 1x10<sup>-5</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of HCl stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL)
+### V<sub>HCl stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.908 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 6 ([H<sup>+</sup>] = 1x10<sup>-6</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of HCl stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL)
+### V<sub>HCl stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.953 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 7 ([H<sup>+</sup>] = 1x10<sup>-7</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of HCl stock
+### V<sub>HCl stock</sub> = 0 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>HCl stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.958 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 8 ([H<sup>+</sup>] = 1x10<sup>-8</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of 0.001 M NaOH stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-6</sup> M)(5 mL)
+### V<sub>NaOH stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.953 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 9 ([H<sup>+</sup>] = 1x10<sup>-9</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of 0.001 M NaOH stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-5</sup> M)(5 mL)
+### V<sub>NaOH stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.908 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 10 ([H<sup>+</sup>] = 1x10<sup>-10</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of 0.001 M NaOH stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1x10<sup>-3</sup> M)V<sub>1</sub> = (1x10<sup>-4</sup> M)(5 mL)
+### V<sub>NaOH stock</sub> = 0.5 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.458 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 11 ([H<sup>+</sup>] = 1x10<sup>-11</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of 1 M NaOH stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1 M)V<sub>1</sub> = (1x10<sup>-3</sup> M)(5 mL)
+### V<sub>NaOH stock</sub> = 0.005 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.953 mL
+# 0.25 mM AuCl<sub>3</sub>, 0 mM fructose, pH 12 ([H<sup>+</sup>] = 1x10<sup>-12</sup> M), 5 mL total
+## Volume of AuCl<sub>3</sub> stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0025 M)V<sub>1</sub> = (0.00025 M)(5 mL)
+### V<sub>AuCl<sub>3</sub> stock</sub> = 0.5 mL
+## Volume of fructose stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (0.0125 M)V<sub>1</sub> = (0.0000625 M)(5 mL)
+### V<sub>fructose stock</sub> = 0.025 mL
+## Volume of 1 M NaOH stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (1 M)V<sub>1</sub> = (1x10<sup>-2</sup> M)(5 mL)
+### V<sub>NaOH stock</sub> = 0.05 mL
+## Volume of Protein stock
+### M<sub>1</sub>V<sub>1</sub> = M<sub>2</sub>V<sub>2</sub>
+### (30 μM)V<sub>Protein Stock</sub> = (3.1 μM))(5 mL)
+### V<sub>Protein Stock</sub> = 0.517 mL
+## Volume of water
+### V<sub>water</sub> = 5 mL - V<sub>AuCl<sub>3</sub> stock</sub> - V<sub>fructose stock</sub> - V<sub>NaOH stock</sub> - V<sub>Protein Stock</sub>
+### V<sub>water</sub> = 3.908 mL
 ==Data==

User:Matt Hartings/Notebook/AU Biomaterials Design Lab/2016/08/29: Difference between revisions

Revision as of 07:32, 30 August 2016

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