User:Melissa Novy/Notebook/CHEM-572/2013/02/19
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(→PLA2002D Films) |
(→ISE Study of PLA2002D + 5 wt% 100Ag-LMT) |
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'''4.47 × 10<sup>-8</sup>mol Ag<sup>+</sup> in 0.025 g 100Ag-LMT of 0.5 g PLA2002D + 5 wt% 100Ag-LMT film''' | '''4.47 × 10<sup>-8</sup>mol Ag<sup>+</sup> in 0.025 g 100Ag-LMT of 0.5 g PLA2002D + 5 wt% 100Ag-LMT film''' | ||
| - | + | ==ISE Study of PLA2002D + 5 wt% 100Ag-LMT== | |
* Calculations: | * Calculations: | ||
** To determine maximum [Ag<sup>+</sup>] possible, assume that all Ag<sup>+</sup> leaches out of solution. | ** To determine maximum [Ag<sup>+</sup>] possible, assume that all Ag<sup>+</sup> leaches out of solution. | ||
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'''(4.47 × 10<sup>-8</sup>mol Ag<sup>+</sup>0 ÷ 0.051 L = 8.76 × 10<sup>-7</sup> M or 0.876 μM''' | '''(4.47 × 10<sup>-8</sup>mol Ag<sup>+</sup>0 ÷ 0.051 L = 8.76 × 10<sup>-7</sup> M or 0.876 μM''' | ||
| + | <br> | ||
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| + | * Protocol | ||
| + | *# Pour 50 mL pure H<sub>2</sub>O into a clean, dry 250-mL Erlenmeyer flask and add 1 mL of 5 M KNO<sub>3</sub>. | ||
| + | *# Measure the conductivity of the solution with the ISE. | ||
| + | *# Place the film into the flask, swirl, and measure the conductivity. | ||
| + | *# Wait 30 min, then measure the conductivity again. | ||
| + | *# Repeat the above step 5 more times. | ||
Revision as of 14:19, 20 February 2013
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Objectives
PLA2002D Films
0.00622 g AgNO3 × (1 mol AgNO3/169.87 g AgNO3) × (1 mol Ag+/1 mol AgNO3) = 3.66 × 10-5 mol Ag+ [Ag+] in 5 mL 100Ag-LMT filtrate was 0.000253614 M 0.000253614 M Ag+ × 0.005 L = 1.2681 × 10-6 mol Ag+ Therefore, 3.66 × 10-5 mol Ag+ − 1.2681 × 10-6 mol Ag+ = 3.53 × 10-5 mol Ag+ was exchanged into 100Ag-LMT.
0.05 × 0.5 g PLA2002D + 5 wt% 100Ag-LMT = 0.025 g 100Ag-LMT (3.53 × 10-5 mol Ag+) ÷ (0.05062 g 100Ag-LMT) = x mol Ag+ ÷ (0.025 g 100Ag-LMT) 4.47 × 10-8mol Ag+ in 0.025 g 100Ag-LMT of 0.5 g PLA2002D + 5 wt% 100Ag-LMT film ISE Study of PLA2002D + 5 wt% 100Ag-LMT
(4.47 × 10-8mol Ag+0 ÷ 0.051 L = 8.76 × 10-7 M or 0.876 μM
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