User:Melissa Novy/Notebook/CHEM-572/2013/02/20
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Calculations
1 μM Ag+ in 50 mL of LB media (0.0105 M Ag+) × V1 = (1×10-6 M) × (50 mL) V1 = 0.00476 mL of 0.0105 M AgNO3 10 μM Ag+ in 50 mL of LB media (0.1 M Ag+) × V1 = (10×10-6 M) × (50 mL) V1 = 0.005 mL of 0.1 M AgNO3
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