User:Michael F. Nagle/Notebook/Chem 571/2012/08/29: Difference between revisions

Revision as of 18:58, 6 December 2012

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Objective

Prepare stock solutions of HAuCl₄ and BSA and use them to make solutions of HAuCl₄ and BSA at varying mole ratios.
- These are to be analyzed by UV/Vis next week to find the optimal mole ratio for nucleation of gold nanoparticles.

Procedure

25mL of stock solution of 7.721mM HAuCl₄ was prepared.
1. (moles HAuCl₄)/.025L H₂O = .01M
2. 2.5*10^-4 mol HAuCl₄ is the amount of gold needed to make this concentration with .025L
3. 2.5*10^-4 mol * 339.785mol/g HAuCl₄ = .0849g HAuCl₄ is needed
4. .0197g of the .0849g stuck to the weigh paper, leaving .0656gHAuCl₄.
5. .0656g HAuCl₄ * (1molHAuCl₄/339.79g/molHAuCl₄)= xM HAuCl₄
6. .007721M HAuCl₄ was the molarity of stock solution made
7. .0849g HAuCl₄ was put in 25mL to make a 10mM solution
25mL stock solution of 15μM BSA was prepared
1. (moles BSA)/.025L = .000015
2. 3.75*10^-7mol BSA is the amount of BSA needded to make a 15μM solution with .025L.
3. 3.75*10^-7mol BSA * 66,463g/mol BSA = .0249g BSA needed
4. .0249g BSA was put in 25mL to make a 15μM solution
6mL solutions were prepared with the mole ratios of (HAuCl₄/BSA) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. .6mL of HAuCl₄ stock was added to each tube, so each was 1.5mM HAuCl₄

The formula m₁v₁=m₂v₂ was used to determine how much BSA was needed for mole ratios (BSA/Au) of 60-170
- 15μM*(volume BSA stock solution) = (1.5*6)
  - 0.6mL BSA stock solution in each tube
- 7720μM*x mL=6mL*(1.5*60μM)
  - 0.069mL HAuCl₄ stock solution
  - 5.331 mL H₂O
- 7720μM*x mL=6mL*(1.5*80μM)
  - 0.093mL HAuCl₄ stock solution
  - 5.307mL H₂O
- 7720μM*x mL=6mL*(1.5*100μM)
  - 0.117mL HAuCl₄ stock solution
  - 5.283mL H₂O
- 7720μM*x mL=6mL*(1.5*120μM)
  - 0.134mL HAuCl₄ stock solution
  - 5.266mL H₂O
- 7720μM*x mL=6mL*(1.5*128μM)
  - 0.149mL HAuCl₄ stock solution
  - 5.251mL H₂O
- 7720μM*x mL=6mL*(1.5*130μM)
  - .152mL HAuCl₄ stock solution
  - 5.248mL H₂O
- 7720μM*x mL=6mL*(1.5*132μM)
  - 0.154mL HAuCl₄ stock solution
  - 5.246mL H₂O
- 7720μM*x mL=6mL*(1.5*133μM)
  - 0.155mL HAuCl₄ stock solution
  - 5.245mL H₂O
- 7720μM*x mL=6mL*(1.5*134μM)
  - 0.156mL HAuCl₄ stock solution
  - 5.254mL H₂O
- 7720μM*x mL=6mL*(1.5*136μM)
  - 0.159mL HAuCl₄ stock solution
  - 5.244mL H₂O
- 7720μM*x mL=6mL*(1.5*138μM)
  - 0.161mL HAuCl₄ stock solution
  - 5.242mL H₂O
- 7720μM*x mL=6mL*(1.5*140μM)
  - 0.163mL HAuCl₄ stock solution
  - 5.237mL H₂O
- 7720μM*x mL=6mL*(1.5*160μM)
  - 0.187mL HAuCl₄ stock solution
  - 5.213mL H₂O
- 7720μM*x mL=6mL*(1.5*170μM)
  - 0.198mL HAuCl₄ stock solution
  - 5.202mL H₂O
- The tubes were capped with tin foil and heated at 85°C for 4 hours.

@@ Line 7: / Line 7: @@
 <!-- ##### DO NOT edit above this line unless you know what you are doing. ##### -->
 ==Objective==
-*Make stock solutions of [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] and [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]
+*Prepare stock solutions of [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] and [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] and use them to make solutions of HAuCl<sub>4</sub> and BSA at varying mole ratios.
+**These are to be analyzed by UV/Vis [[User:Michael_F._Nagle/Notebook/Chem_571/2012/09/04|next week]] to find the optimal mole ratio for nucleation of gold nanoparticles.
-*'''[[User:Abigail E. Miller|Abigail E. Miller]] 14:02, 17 September 2012 (EDT)''':didn't you also make various ratio solutions foHAuCl4 to BSA to synthesize AuNPs?
 ==Procedure==
-#A stock solution of [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was made, with the attempted Molarity of 10mM.
+#25mL of stock solution of 7.721mM [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was prepared.
 ## (moles [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])/.025L H<sub>2</sub>O = .01M
-## 2.5*10<sup>-4</sup> mol [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
+## 2.5*10<sup>-4</sup> mol [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] is the amount of gold needed to make this concentration with .025L
-## 2.5*10<sup>-4</sup> mol * 339.785mol/g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] = .0849g
+## 2.5*10<sup>-4</sup> mol * 339.785mol/g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] = .0849g HAuCl<sub>4</sub> is needed
 ## .0197g of the .0849g stuck to the weigh paper, leaving .0656g[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]].
 ## .0656g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] * (1mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]/339.79g/mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])= xM [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
-## .007721M [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
+## .007721M [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was the molarity of stock solution made
 ## .0849g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was put in 25mL to make a 10mM solution
-#A 15μM stock solution of [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was made
+#25mL stock solution of 15μM [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was prepared
 ## (moles [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]])/.025L = .000015
-## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]
+## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] is the amount of BSA needded to make a 15μM solution with .025L.
-## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] * 66,463g/mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] = .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]
+## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] * 66,463g/mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] = .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] needed
 ## .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was put in 25mL to make a 15μM solution
+#6mL solutions were prepared with the mole ratios of ([[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]/[[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. .6mL of HAuCl<sub>4</sub> stock was added to each tube, so each was 1.5mM HAuCl<sub>4</sub>
-*'''[[User:Abigail E. Miller|Abigail E. Miller]] 14:03, 17 September 2012 (EDT)''':while good, this needs more description. what are the numbers that you are listing? theoretical concentration? actual mass added? actual concentration? etc.
+*The formula m<sub>1</sub>v<sub>1</sub>=m<sub>2</sub>v<sub>2</sub> was used to determine how much BSA was needed for mole ratios (BSA/Au) of 60-170
+**15μM*(volume [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] stock solution) = (1.5*6)
-==Results==
+***0.6mL [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] stock solution in each tube
-*The BSA solution created was 15μM
+**7720μM*x mL=6mL*(1.5*60μM)
-*The actual molarity for the HAuCl<sub>4</sub> stock solution created turned out to be 7.721mM rather than 10mM. This is because unlike BSA, which is easy to handle, HAuCl4 comes in large chunks which don't break easily and melts, leaving residue on the weigh paper.
+***0.069mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.331 mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*80μM)
+***0.093mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.307mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*100μM)
+***0.117mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.283mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*120μM)
+***0.134mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.266mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*128μM)
+***0.149mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.251mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*130μM)
+***.152mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.248mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*132μM)
+***0.154mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.246mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*133μM)
+***0.155mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.245mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*134μM)
+***0.156mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.254mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*136μM)
+***0.159mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.244mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*138μM)
+***0.161mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.242mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*140μM)
+***0.163mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.237mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*160μM)
+***0.187mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.213mL H<sub>2</sub>O
+**7720μM*x mL=6mL*(1.5*170μM)
+***0.198mL [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] stock solution
+***5.202mL H<sub>2</sub>O
+**The tubes were capped with tin foil and heated at 85°C for 4 hours.
-*'''[[User:Abigail E. Miller|Abigail E. Miller]] 14:04, 17 September 2012 (EDT)''':it is hydroscopic, meaning it absorbes water and then dissolves in that water not melting.
-<!-- ##### DO NOT edit below this line unless you know what you are doing. ##### -->
-|}
 __NOTOC__

User:Michael F. Nagle/Notebook/Chem 571/2012/08/29: Difference between revisions

Revision as of 18:58, 6 December 2012

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