User:Michael F. Nagle/Notebook/Chem 571/2012/08/29: Difference between revisions

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#A stock solution of [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was made, with the attempted Molarity of 10mM.
#A stock solution of [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was made, with the attempted Molarity of 10mM.
## (moles [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])/.025L H<sub>2</sub>O = .01M
## (moles [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])/.025L H<sub>2</sub>O = .01M
## 2.5*10<sup>-4</sup> mol [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
## 2.5*10<sup>-4</sup> mol [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] is the amount of gold needed to make this concentration with .025L
## 2.5*10<sup>-4</sup> mol * 339.785mol/g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] = .0849g  
## 2.5*10<sup>-4</sup> mol * 339.785mol/g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] = .0849g HAuCl<sub>4</sub> is needed
## .0197g of the .0849g stuck to the weigh paper, leaving .0656g[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]].
## .0197g of the .0849g stuck to the weigh paper, leaving .0656g[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]].
## .0656g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] * (1mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]/339.79g/mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])= xM [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
## .0656g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] * (1mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]/339.79g/mol[[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]])= xM [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
## .007721M [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]]
## .007721M [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was the molarity of stock solution made
## .0849g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was put in 25mL to make a 10mM solution
## .0849g [[AU_Biomaterials_Design_Lab:Materials/HAuCl4|HAuCl<sub>4</sub>]] was put in 25mL to make a 10mM solution
#A 15μM stock solution of [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was made
#A 15μM stock solution of [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was made
## (moles [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]])/.025L = .000015
## (moles [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]])/.025L = .000015
## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]
## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] is the amount of BSA needded to make a 15μM solution with .025L.
## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] * 66,463g/mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] = .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]]
## 3.75*10^-7mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] * 66,463g/mol [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] = .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] needed
## .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was put in 25mL to make a 15μM solution
## .0249g [[AU_Biomaterials_Design_Lab:Materials/BSA|BSA]] was put in 25mL to make a 15μM solution
*'''[[User:Abigail E. Miller|Abigail E. Miller]] 14:03, 17 September 2012 (EDT)''':while good, this needs more description. what are the numbers that you are listing? theoretical concentration? actual mass added? actual concentration? etc.


==Results==
==Results==

Revision as of 11:13, 18 September 2012

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Objective

  • Abigail E. Miller 14:02, 17 September 2012 (EDT):didn't you also make various ratio solutions foHAuCl4 to BSA to synthesize AuNPs?

Procedure

  1. A stock solution of HAuCl4 was made, with the attempted Molarity of 10mM.
    1. (moles HAuCl4)/.025L H2O = .01M
    2. 2.5*10-4 mol HAuCl4 is the amount of gold needed to make this concentration with .025L
    3. 2.5*10-4 mol * 339.785mol/g HAuCl4 = .0849g HAuCl4 is needed
    4. .0197g of the .0849g stuck to the weigh paper, leaving .0656gHAuCl4.
    5. .0656g HAuCl4 * (1molHAuCl4/339.79g/molHAuCl4)= xM HAuCl4
    6. .007721M HAuCl4 was the molarity of stock solution made
    7. .0849g HAuCl4 was put in 25mL to make a 10mM solution
  2. A 15μM stock solution of BSA was made
    1. (moles BSA)/.025L = .000015
    2. 3.75*10^-7mol BSA is the amount of BSA needded to make a 15μM solution with .025L.
    3. 3.75*10^-7mol BSA * 66,463g/mol BSA = .0249g BSA needed
    4. .0249g BSA was put in 25mL to make a 15μM solution

Results

  • The BSA solution created was 15μM
  • The actual molarity for the HAuCl4 stock solution created turned out to be 7.721mM rather than 10mM. This is because unlike BSA, which is easy to handle, HAuCl4 comes in large chunks which don't break easily and melts, leaving residue on the weigh paper.
  • Abigail E. Miller 14:04, 17 September 2012 (EDT):it is hydroscopic, meaning it absorbes water and then dissolves in that water not melting.


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