Objective
 Prepare stock solutions of HAuCl_{4} and BSA and use them to make solutions of HAuCl_{4} and BSA at varying mole ratios.
 These are to be analyzed by UV/Vis next week to find the optimal mole ratio for nucleation of gold nanoparticles.
Procedure
 25mL of stock solution of 7.721mM HAuCl_{4} was prepared.
 (moles HAuCl_{4})/.025L H_{2}O = .01M
 2.5*10^{4} mol HAuCl_{4} is the amount of gold needed to make this concentration with .025L
 2.5*10^{4} mol * 339.785mol/g HAuCl_{4} = .0849g HAuCl_{4} is needed
 .0197g of the .0849g stuck to the weigh paper, leaving .0656gHAuCl_{4}.
 .0656g HAuCl_{4} * (1molHAuCl_{4}/339.79g/molHAuCl_{4})= xM HAuCl_{4}
 .007721M HAuCl_{4} was the molarity of stock solution made
 .0849g HAuCl_{4} was put in 25mL to make a 10mM solution
 25mL stock solution of 15μM BSA was prepared
 (moles BSA)/.025L = .000015
 3.75*10^7mol BSA is the amount of BSA needded to make a 15μM solution with .025L.
 3.75*10^7mol BSA * 66,463g/mol BSA = .0249g BSA needed
 .0249g BSA was put in 25mL to make a 15μM solution
 6mL solutions were prepared with the mole ratios of (HAuCl_{4}/BSA) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. .6mL of HAuCl_{4} stock was added to each tube, so each was 1.5mM HAuCl_{4}
 The formula m_{1}v_{1}=m_{2}v_{2} was used to determine how much BSA was needed for mole ratios (BSA/Au) of 60170
 15μM*(volume BSA stock solution) = (1.5*6)
 0.6mL BSA stock solution in each tube
 7720μM*x mL=6mL*(1.5*60μM)
 0.069mL HAuCl_{4} stock solution
 5.331 mL H_{2}O
 7720μM*x mL=6mL*(1.5*80μM)
 0.093mL HAuCl_{4} stock solution
 5.307mL H_{2}O
 7720μM*x mL=6mL*(1.5*100μM)
 0.117mL HAuCl_{4} stock solution
 5.283mL H_{2}O
 7720μM*x mL=6mL*(1.5*120μM)
 0.134mL HAuCl_{4} stock solution
 5.266mL H_{2}O
 7720μM*x mL=6mL*(1.5*128μM)
 0.149mL HAuCl_{4} stock solution
 5.251mL H_{2}O
 7720μM*x mL=6mL*(1.5*130μM)
 .152mL HAuCl_{4} stock solution
 5.248mL H_{2}O
 7720μM*x mL=6mL*(1.5*132μM)
 0.154mL HAuCl_{4} stock solution
 5.246mL H_{2}O
 7720μM*x mL=6mL*(1.5*133μM)
 0.155mL HAuCl_{4} stock solution
 5.245mL H_{2}O
 7720μM*x mL=6mL*(1.5*134μM)
 0.156mL HAuCl_{4} stock solution
 5.254mL H_{2}O
 7720μM*x mL=6mL*(1.5*136μM)
 0.159mL HAuCl_{4} stock solution
 5.244mL H_{2}O
 7720μM*x mL=6mL*(1.5*138μM)
 0.161mL HAuCl_{4} stock solution
 5.242mL H_{2}O
 7720μM*x mL=6mL*(1.5*140μM)
 0.163mL HAuCl_{4} stock solution
 5.237mL H_{2}O
 7720μM*x mL=6mL*(1.5*160μM)
 0.187mL HAuCl_{4} stock solution
 5.213mL H_{2}O
 7720μM*x mL=6mL*(1.5*170μM)
 0.198mL HAuCl_{4} stock solution
 5.202mL H_{2}O
 The tubes were capped with tin foil and heated at 85°C for 4 hours.
