User:Michael F. Nagle/Notebook/Chem 571/2012/09/05: Difference between revisions

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3.8236*10<sup>-7</sup> mol BSA / .025L H2O = 1.52944*10<sup>-5</sup> M BSA
3.8236*10<sup>-7</sup> mol BSA / .025L H2O = 1.52944*10<sup>-5</sup> M BSA


m1v1=m2v2
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*120)
x = .14362mL AuNP solution
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*128)
x = .15319mL AuNP solution
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*130)
x = .15558mL AuNP solution
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*132)
x = .15797mL AuNP solution
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*133)
x = .15917mL AuNP solution
7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*134)
x = .16037mL AuNP solution


 
6-.14362mL AuNP solution
 
6-.15319mL AuNP solution
6-.15558mL AuNP solution
6-.15797mL AuNP solution
6-.15917mL AuNP solution
6-.16037mL AuNP solution
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__NOTOC__
__NOTOC__

Revision as of 12:55, 5 September 2012

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Entry title

  • A 7.522*10-3M solution of HAuCl4 was used to make varying concentrations of gold nanoparticles and BSA.
  • A BSA solution was made with .0254g BSA in .025L H2O

.0254g BSA / 66430g/mol BSA = 3.8236*10-7 mol BSA

3.8236*10-7 mol BSA / .025L H2O = 1.52944*10-5 M BSA

m1v1=m2v2 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*120) x = .14362mL AuNP solution 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*128) x = .15319mL AuNP solution 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*130) x = .15558mL AuNP solution 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*132) x = .15797mL AuNP solution 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*133) x = .15917mL AuNP solution 7520mM AuNP * (volume AuNP solution) = 6mL H2O * (1.5*134) x = .16037mL AuNP solution

6-.14362mL AuNP solution 6-.15319mL AuNP solution 6-.15558mL AuNP solution 6-.15797mL AuNP solution 6-.15917mL AuNP solution 6-.16037mL AuNP solution


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