User:Puja Mody/Notebook/Chem 571: Gold Nanoparticles/2012/09/25
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 500 mM0.50.5   500 mM0.50.5  
    
    +   1 M01 
}  }  
+  to make a 25mL stock solution of the tris buffer at a pH of 10  
+  1mol/L x .025= .025 mol  
+  .025 mol x 121.14 g/mol = 3.0285 g of tris  
+  To get the necessary concentrations of tris into the gold/BSA solutions, the M<sub>1</sub>V<sub>1</sub>=M<sub>2</sub>V<sub>2</sub> formula was used to calculate the volume of tris needed. From there, the value of the volume of tris was subtracted from 1 in order to determine the amount of water that would be added to make the desired concentration.  
==Conclusions==  ==Conclusions== 
Revision as of 04:55, 26 September 2012
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Separate ProteinsGoals
Procedure
DATA/Calculations
to make a 25mL stock solution of the tris buffer at a pH of 10 1mol/L x .025= .025 mol .025 mol x 121.14 g/mol = 3.0285 g of tris To get the necessary concentrations of tris into the gold/BSA solutions, the M_{1}V_{1}=M_{2}V_{2} formula was used to calculate the volume of tris needed. From there, the value of the volume of tris was subtracted from 1 in order to determine the amount of water that would be added to make the desired concentration. Conclusions
