User:Sarah Burkhard/Notebook/471 Nano Notebook/2017/02/21
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Objectives
preparation of gold solutionsto get to pH 4 we will add: 300 uL of 5 mM HAuCL, (240*2) 480 uL of 5 mM NaOH, 2220 uL of neutralized water to get to pH 5 we will add 300 uL of 5 mM HAuCl, 1470 uL of 1 mM NaOH = (1470*2/5) 588 uL 5mM NaOH, 2112 uL of neutralized water to get to pH 6 we will add 300 uL of 5 mM HAuCL, 1497 uL of 1 mM NaOH = (1497*2/5) 599 uL 5mM NaOH, 2101 uL of neutralized water to get to pH 7 we will add 300 uL of 5 mM HAuCl, (300*2) 600 uL 5 mM NaOH, 2100 uL of neutralized water to get pH 8 we will add 300 uL of 5 mM HAuCl, (300*2) 600 uL 5 mM NaOH, (3*2) 6 uL 1 mM NaOH, 2094 uL of neutralized water Observations
Analysis |