Physics307L:People/Giannini/Scratch Sheet

$L_1=q_1\lambda_1/2n\,\!$

$L_2=q_2\lambda_2/2n\,\!$

which gives us:

Eq.1 $c=\nu_1\lambda_1\,\!$

Eq.2 $c=\nu_2\lambda_2\,\!$

Now we say

Eq.3 $\Delta\nu=\nu_1-\nu_2\,\!$

then we can use $2\cdot Eq.1 - 2\cdot Eq.2$

which then gives us

$c=2\nu_1\lambda_1-\nu_2\lambda_2\,\!$

which, upon substitution of Eq.3, we get

$c=\nu_1(2\lambda_1-\lambda_2)+\Delta\nu\lambda_2\,\!$

$TEM_{00}\,\!$

$TEM_{01}\,\!$

$TEM_{10}\,\!$

$TEM_{11}\,\!$