User:Michael F. Nagle/Notebook/Chem 571/2012/08/29

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Objective

  • Prepare stock solutions of HAuCl4 and BSA and use them to make solutions of HAuCl4 and BSA at varying mole ratios.
    • These are to be analyzed by UV/Vis next week to find the optimal mole ratio for nucleation of gold nanoparticles.

Procedure

  1. 25mL of stock solution of 7.721mM HAuCl4 was prepared.
    1. (moles HAuCl4)/.025L H2O = .01M
    2. 2.5*10-4 mol HAuCl4 is the amount of gold needed to make this concentration with .025L
    3. 2.5*10-4 mol * 339.785mol/g HAuCl4 = .0849g HAuCl4 is needed
    4. .0197g of the .0849g stuck to the weigh paper, leaving .0656gHAuCl4.
    5. .0656g HAuCl4 * (1molHAuCl4/339.79g/molHAuCl4)= xM HAuCl4
    6. .007721M HAuCl4 was the molarity of stock solution made
    7. .0849g HAuCl4 was put in 25mL to make a 10mM solution
  2. 25mL stock solution of 15μM BSA was prepared
    1. (moles BSA)/.025L = .000015
    2. 3.75*10^-7mol BSA is the amount of BSA needded to make a 15μM solution with .025L.
    3. 3.75*10^-7mol BSA * 66,463g/mol BSA = .0249g BSA needed
    4. .0249g BSA was put in 25mL to make a 15μM solution
  3. 6mL solutions were prepared with the mole ratios of (HAuCl4/BSA) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. .6mL of HAuCl4 stock was added to each tube, so each was 1.5mM HAuCl4
  • The formula m1v1=m2v2 was used to determine how much BSA was needed for mole ratios (BSA/Au) of 60-170
    • 15μM*(volume BSA stock solution) = (1.5*6)
      • 0.6mL BSA stock solution in each tube
    • 7720μM*x mL=6mL*(1.5*60μM)
      • 0.069mL HAuCl4 stock solution
      • 5.331 mL H2O
    • 7720μM*x mL=6mL*(1.5*80μM)
      • 0.093mL HAuCl4 stock solution
      • 5.307mL H2O
    • 7720μM*x mL=6mL*(1.5*100μM)
      • 0.117mL HAuCl4 stock solution
      • 5.283mL H2O
    • 7720μM*x mL=6mL*(1.5*120μM)
      • 0.134mL HAuCl4 stock solution
      • 5.266mL H2O
    • 7720μM*x mL=6mL*(1.5*128μM)
      • 0.149mL HAuCl4 stock solution
      • 5.251mL H2O
    • 7720μM*x mL=6mL*(1.5*130μM)
      • .152mL HAuCl4 stock solution
      • 5.248mL H2O
    • 7720μM*x mL=6mL*(1.5*132μM)
      • 0.154mL HAuCl4 stock solution
      • 5.246mL H2O
    • 7720μM*x mL=6mL*(1.5*133μM)
      • 0.155mL HAuCl4 stock solution
      • 5.245mL H2O
    • 7720μM*x mL=6mL*(1.5*134μM)
      • 0.156mL HAuCl4 stock solution
      • 5.254mL H2O
    • 7720μM*x mL=6mL*(1.5*136μM)
      • 0.159mL HAuCl4 stock solution
      • 5.244mL H2O
    • 7720μM*x mL=6mL*(1.5*138μM)
      • 0.161mL HAuCl4 stock solution
      • 5.242mL H2O
    • 7720μM*x mL=6mL*(1.5*140μM)
      • 0.163mL HAuCl4 stock solution
      • 5.237mL H2O
    • 7720μM*x mL=6mL*(1.5*160μM)
      • 0.187mL HAuCl4 stock solution
      • 5.213mL H2O
    • 7720μM*x mL=6mL*(1.5*170μM)
      • 0.198mL HAuCl4 stock solution
      • 5.202mL H2O
    • The tubes were capped with tin foil and heated at 85°C for 4 hours.


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