User:Nader A. Khamis/Notebook/Experimental Biological Chemistry AU Fall 2011/2011/12/07

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Objective

  • Obtain a purple solution for the HAuCl4 to BSA molar ratio of 166.
  • Obtain fibers for the HAuCl4 to BSA molar ratio of 70.

Description

Two solutions were prepared in eppendorf tubes.

Solution A which contains a molar ratio of HAuCl4 to BSA equal to 70 was prepared using the following procedure.

  1. 0.05mL of HAuCl4 (2.9mM), 0.1mL of BSA (17.7µM) and 0.2mL of H2O were pipetted into an eppendorf tube.
  2. The tube was placed in the 80°C heatblock for 2 hours.
  3. The tube was removed and shaken.

Solution B, which contains a molar ratio of HAuCl4 to BSA equal to 166 was prepared using the following procedure.

  1. 0.1mL of HAuCl4 (2.9mM), 0.1mL of BSA (17.7µM) and 0.8ml of H2O were pipetted into an eppendorf tube.
  2. The tube was placed in the 80°C heatblock for 1 hour.
  3. The tube was removed and placed in ice.

Data

  • For the HAuCl4 to BSA molar ratio of 70 we obtained a purple solution which is what we obtained on December 6th, 2011.
  • For the 166 molar ratio, we obtained a purple solution, which is what we obtained on December 6th, 2011.

Image:7dec-GoldNPs result.jpg

Notes

  • Placing HAuCl4/BSA/H2O in a heat block and then transferring it into ice prevented the spontaneous formation of fibers.

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