User:Mary Mendoza/Notebook/CHEM 571 Experimental Biological Chemistry I/2012/10/16
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PCR mutation
0.46 mg = 0.46E6 ng
V1 = [math]\displaystyle{ \frac{100 ng/ \mu L * 1000 \mu L}{0.46E3 ng/ \mu L} }[/math] = 217.39 μL |