User:Michael F. Nagle/Notebook/Chem 571/2012/09/04

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Objective

  • Find optimal mole ratio of HAuCl4 to BSA for formation of gold nanoparticles

Procedure

  1. Solutions were made with the mole ratios of (HAuCl4/BSA) 60, 80, 100, 120, 128, 130, 132, 133, 134, 136, 138, 140, 160, and 170. Volume of HAuCl4 stock solution was calculated for each tube and inserted. The water needed for each tube was calculated by subtracting the volume of HAuCl4 stock solution and BSA stock solution from 6mL.
    1. m1v1=m2v2
    2. 15μM*(volume BSA stock solution) = (1.5*6)
      1. 0.6mL BSA stock solution in each tube
    3. 7720μM*x mL=6mL*(1.5*60μM)
      1. 0.069mL HAuCl4 stock solution
      2. 5.331 mL H2O
    4. 7720μM*x mL=6mL*(1.5*80μM)
      1. 0.093mL HAuCl4 stock solution
      2. 5.307mL H2O
    5. 7720μM*x mL=6mL*(1.5*100μM)
      1. 0.117mL HAuCl4 stock solution
      2. 5.283mL H2O
    6. 7720μM*x mL=6mL*(1.5*120μM)
      1. 0.134mL HAuCl4 stock solution
      2. 5.266mL H2O
    7. 7720μM*x mL=6mL*(1.5*128μM)
      1. 0.149mL HAuCl4 stock solution
      2. 5.251mL H2O
    8. 7720μM*x mL=6mL*(1.5*130μM)
      1. .152mL HAuCl4 stock solution
      2. 5.248mL H2O
    9. 7720μM*x mL=6mL*(1.5*132μM)
      1. 0.154mL HAuCl4 stock solution
      2. 5.246mL H2O
    10. 7720μM*x mL=6mL*(1.5*133μM)
      1. 0.155mL HAuCl4 stock solution
      2. 5.245mL H2O
    11. 7720μM*x mL=6mL*(1.5*134μM)
      1. 0.156mL HAuCl4 stock solution
      2. 5.254mL H2O
    12. 7720μM*x mL=6mL*(1.5*136μM)
      1. 0.159mL HAuCl4 stock solution
      2. 5.244mL H2O
    13. 7720μM*x mL=6mL*(1.5*138μM)
      1. 0.161mL HAuCl4 stock solution
      2. 5.242mL H2O
    14. 7720μM*x mL=6mL*(1.5*140μM)
      1. 0.163mL HAuCl4 stock solution
      2. 5.237mL H2O
    15. 7720μM*x mL=6mL*(1.5*160μM)
      1. 0.187mL HAuCl4 stock solution
      2. 5.213mL H2O
    16. 7720μM*x mL=6mL*(1.5*170μM)
      1. 0.198mL HAuCl4 stock solution
      2. 5.202mL H2O
  2. The tubes were wrapped in tin foil and heated at 80°C for 4 hours.


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