User:Douglas M. Fox/Notebook/AU CHEM-571 F2011 Lab Support/2014/07/25: Difference between revisions

From OpenWetWare
Jump to navigationJump to search
(Autocreate 2014/07/25 Entry for User:Douglas_M._Fox/Notebook/AU_CHEM-571_F2011_Lab_Support)
 
No edit summary
Line 6: Line 6:
| colspan="2"|
| colspan="2"|
<!-- ##### DO NOT edit above this line unless you know what you are doing. ##### -->
<!-- ##### DO NOT edit above this line unless you know what you are doing. ##### -->
==Entry title==
==Protein Solution Preparation==
* Insert content here...
# Lysozyme
 
#*M<sub>w</sub> = 14,307 Da
#*0.00637 g in 25 mL vol flask (17.81 μM)
#*0.02538 g in 25 mL vol flask (70.96 μM = 1.01 g/L)
# BSA
#*M<sub>w</sub> = 66,430 Da
#*0.02944 g in 25 mL vol flask (17.73 μM = 1.18 g/L)
# Invertase
#*M<sub>w</sub> = 270,000 Da
#*0.09497 g in 10 mL vol flask (35.2 μM = 9.56 g/L)
#*Did not completely dissolve
<br>
General Procedure for determining appropriate concentration:
*Identify [Au]:[protein] concentration required for fiber formation
*[Au]<sub>f</sub> = 0.25 mM = 250 μM for correct pH
*Want to add 1 mL of each stock, diluted to 10 mL for fiber formation
*[Au]<sub>stock</sub> = 2.5 mM
*For BSA, fiber formation occurs at [Au]:[protein] = 135
*[Protein] = [Au]/135 = 18.5 μM
*Note that the final prepared solution will have [protein]<sub>f</sub> = 1.85 μM


<!-- ##### DO NOT edit below this line unless you know what you are doing. ##### -->
<!-- ##### DO NOT edit below this line unless you know what you are doing. ##### -->

Revision as of 05:09, 10 September 2014

Project name <html><img src="/images/9/94/Report.png" border="0" /></html> Main project page
Next entry<html><img src="/images/5/5c/Resultset_next.png" border="0" /></html>

Protein Solution Preparation

  1. Lysozyme
    • Mw = 14,307 Da
    • 0.00637 g in 25 mL vol flask (17.81 μM)
    • 0.02538 g in 25 mL vol flask (70.96 μM = 1.01 g/L)
  2. BSA
    • Mw = 66,430 Da
    • 0.02944 g in 25 mL vol flask (17.73 μM = 1.18 g/L)
  3. Invertase
    • Mw = 270,000 Da
    • 0.09497 g in 10 mL vol flask (35.2 μM = 9.56 g/L)
    • Did not completely dissolve


General Procedure for determining appropriate concentration:

  • Identify [Au]:[protein] concentration required for fiber formation
  • [Au]f = 0.25 mM = 250 μM for correct pH
  • Want to add 1 mL of each stock, diluted to 10 mL for fiber formation
  • [Au]stock = 2.5 mM
  • For BSA, fiber formation occurs at [Au]:[protein] = 135
  • [Protein] = [Au]/135 = 18.5 μM
  • Note that the final prepared solution will have [protein]f = 1.85 μM